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The following reaction systems are at equilibrium in separate sealed containers - VCE - SSCE Chemistry - Question 7 - 2010 - Paper 1

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The following reaction systems are at equilibrium in separate sealed containers. The volumes of the containers are halved at constant temperature. Which reaction ha... show full transcript

Worked Solution & Example Answer:The following reaction systems are at equilibrium in separate sealed containers - VCE - SSCE Chemistry - Question 7 - 2010 - Paper 1

Step 1

A. N2(g) ⇌ 2NO(g)

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Answer

This reaction involves one mole of gas on the reactants' side (N2) and two moles on the products' side (2NO). Halving the volume increases the concentration of all species. The change in reaction quotient will be noticeable since the effect on products will be more significant, resulting in a larger percentage change.

Percentage change calculation: ext{Percentage Change} = rac{ ext{New Concentration} - ext{Old Concentration}}{ ext{Old Concentration}} imes 100

Step 2

B. H2(g) + I2(g) ⇌ 2HI(g)

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Answer

This reaction has one mole of reactants (H2 and I2) and produces two moles of HI. Halving the volume will similarly increase the concentration, but the ratio change will be smaller compared to option A.

Percentage change calculation would yield a smaller percentage change.

Step 3

C. 2CO(g) ⇌ 2C(g) + O2(g)

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Answer

This reaction has two moles of gas on both sides (2CO vs 2C + O2). The volume change will result in increased concentrations, but with equal numbers of moles, the reaction quotient effectively balances out, leading to a smaller percentage change.

Step 4

D. CO(g) + 2H2(g) ⇌ CH3OH(g)

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Answer

This reaction has three moles of gas on the left (CO + 2H2) and one on the right (CH3OH). The decrease in volume will also increase the concentrations, but the net effect will be less pronounced as there is a larger number of gaseous reactants compared to products, leading to a moderate change.

Step 5

Conclusion

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Answer

Among these, reaction A (N2(g) ⇌ 2NO(g)) results in the largest percentage change in concentration after the volume halving because it significantly favors product formation, based on the change in mole ratio.

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