Consider the following TLC plate of compounds X, Y and Z developed using a suitable mobile phase on a polar stationary phase - VCE - SSCE Chemistry - Question 6 - 2010 - Paper 1

From the given TLC plate, we observe that compound X is the closest to the origin, indicating it is the most polar. To find the Rf value, we can use the formula:

$Rf = \frac{distance\:travelled\:by\:compound}{distance\:travelled\:by\:solvent}$

Looking at the scale, we can estimate that the distance travelled by compound X is approximately 0.29 cm, while the distance travelled by the solvent front is approximately 3.20 cm. Thus:

$Rf = \frac{0.29}{3.20} \approx 0.09$

Since X is the most polar component, we can conclude it has the lowest Rf value.

Based on the Rf values we deduced, the value closest to our calculation from the options provided is A. 0.29. Hence, this is the answer.