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Consider the following information - VCE - SSCE Chemistry - Question 6 - 2007 - Paper 1

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Consider the following information. Ethanol burns in excess air according to the following equation. C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) ΔH = -1364 kJ mol⁻¹ T... show full transcript

Worked Solution & Example Answer:Consider the following information - VCE - SSCE Chemistry - Question 6 - 2007 - Paper 1

Step 1

i. Calculate the minimum amount of energy, in kJ, required to heat 550 g of water and the pot from 18.5°C to 100.0°C.

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Answer

To find the total energy required, we can use the formula:

Q=mcΔTQ = mcΔT

Where:

  • QQ = energy (in J)
  • mm = mass (in g)
  • cc = specific heat capacity (in J g⁻¹ °C⁻¹)
  • ΔTΔT = change in temperature (in °C)

First, calculate the energy required to heat the water:

  1. For the water:

    • mwater=550gm_{water} = 550 g
    • cwater=4.18Jg1°C1c_{water} = 4.18 J g⁻¹ °C⁻¹
    • ΔTwater=100.018.5=81.5°CΔT_{water} = 100.0 - 18.5 = 81.5 °C

    Thus,

    Qwater=550imes4.18imes81.5=198,198extJQ_{water} = 550 imes 4.18 imes 81.5 = 198,198 ext{ J}

  2. For the pot (aluminium):

    • mpot=150gm_{pot} = 150 g
    • cpot=9.000Jg1°C1c_{pot} = 9.000 J g⁻¹ °C⁻¹
    • ΔTpot=100.018.5=81.5°CΔT_{pot} = 100.0 - 18.5 = 81.5 °C

    Thus,

    Qpot=150imes9.000imes81.5=1,096.25extJQ_{pot} = 150 imes 9.000 imes 81.5 = 1,096.25 ext{ J}

Total energy required:

Qtotal=Qwater+Qpot=198,198+1,096.25=199,294.25extJextor199.29extkJQ_{total} = Q_{water} + Q_{pot} = 198,198 + 1,096.25 = 199,294.25 ext{ J} ext{ or } 199.29 ext{ kJ}

Step 2

ii. Calculate the mass, in g, of ethanol that needs to be completely burnt to provide this energy.

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Answer

Using the given enthalpy change for the combustion of ethanol:

ΔH=1364extkJmol1ΔH = -1364 ext{ kJ mol}^{-1}

To find the number of moles of ethanol required:

  1. Convert the energy to be provided into kJ:
    Qrequired=199.29extkJQ_{required} = 199.29 ext{ kJ}

  2. Calculate moles required:

    ext{Moles of ethanol} = rac{Q_{required}}{-ΔH} = rac{199.29}{1364} = 0.146 ext{ mol}

  3. Now, calculate the mass:

    • Molar mass of ethanol, C2H5OH=2(12)+6(1)+16=46extgmol1C_2H_5OH = 2(12) + 6(1) + 16 = 46 ext{ g mol}^{-1}

    extMassofethanol=0.146extmolimes46extgmol1=6.70extg ext{Mass of ethanol} = 0.146 ext{ mol} imes 46 ext{ g mol}^{-1} = 6.70 ext{ g}

Step 3

iii. Only 35% of the energy released by the combustion of ethanol is transferred to the cooking pot and contents. Calculate the mass, in g, of ethanol that needs to be burnt in practice to heat the water and the pot from 18.5°C to 100.0°C.

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Answer

Since only 35% of the energy is useful,

  1. Calculate the energy that actually contributes:

    Qeffective=0.35imes199.29extkJ=69.75extkJQ_{effective} = 0.35 imes 199.29 ext{ kJ} = 69.75 ext{ kJ}

  2. Now, calculate the moles of ethanol needed:

    ext{Moles needed} = rac{Q_{effective}}{-ΔH} = rac{69.75}{1364} = 0.0512 ext{ mol}

  3. Finally, calculate the mass of ethanol:

    extMassofethanol=0.0512extmolimes46extgmol1=2.36extg ext{Mass of ethanol} = 0.0512 ext{ mol} imes 46 ext{ g mol}^{-1} = 2.36 ext{ g}

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