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In an experiment, 172.1 g of gypsum, CaSO₄·2H₂O (M = 172.1 g mol⁻¹), was heated to constant mass in a large crucible - VCE - SSCE Chemistry - Question 13 - 2011 - Paper 1

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Question 13

In-an-experiment,-172.1-g-of-gypsum,-CaSO₄·2H₂O-(M-=-172.1-g-mol⁻¹),-was-heated-to-constant-mass-in-a-large-crucible-VCE-SSCE Chemistry-Question 13-2011-Paper 1.png

In an experiment, 172.1 g of gypsum, CaSO₄·2H₂O (M = 172.1 g mol⁻¹), was heated to constant mass in a large crucible. The loss in mass of the crucible and contents w... show full transcript

Worked Solution & Example Answer:In an experiment, 172.1 g of gypsum, CaSO₄·2H₂O (M = 172.1 g mol⁻¹), was heated to constant mass in a large crucible - VCE - SSCE Chemistry - Question 13 - 2011 - Paper 1

Step 1

The reaction that occurred when the gypsum was heated was

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Answer

The mass loss during the heating of gypsum indicates the release of water molecules. The correct reaction is:

CaSO42H2O(s)CaSO4(s)+2H2O(g)CaSO₄·2H₂O(s) \rightarrow CaSO₄(s) + 2H₂O(g)

Therefore, the correct answer is A.

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