947 J of energy is required to raise the temperature of 125 g of stainless steel by 15.7°C - VCE - SSCE Chemistry - Question 1 - 2003 - Paper 1

To find the specific heat capacity (c), we can use the formula:

$c = \frac{Q}{m \Delta T}$

Where:

• $Q$ = Energy supplied = 947 J
• $m$ = Mass of the substance = 125 g
• $\Delta T$ = Change in temperature = 15.7°C

Now, substituting the values into the formula:

$c = \frac{947 \text{ J}}{125 \text{ g} \times 15.7 \text{°C}}$

Calculating the denominator:

$125 \times 15.7 = 1962.5$

Now, substituting back:

$c = \frac{947}{1962.5} \approx 0.483 \, \text{J g}^{-1} \, \text{°C}^{-1}$

Thus, the specific heat capacity of stainless steel is approximately 0.483 J g⁻¹ °C⁻¹, which corresponds to option B.