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One litre of air at atmospheric pressure and 25°C is held in a flask - VCE - SSCE Chemistry - Question 17 - 2005 - Paper 1

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One litre of air at atmospheric pressure and 25°C is held in a flask. The pressure of oxygen in the flask is 0.201 atm (20.4 kPa). The concentration of oxygen in th... show full transcript

Worked Solution & Example Answer:One litre of air at atmospheric pressure and 25°C is held in a flask - VCE - SSCE Chemistry - Question 17 - 2005 - Paper 1

Step 1

Calculate the number of moles of oxygen

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Answer

To find the concentration of oxygen in the flask, we can use the ideal gas law, which states:

PV=nRTPV = nRT

Where:

  • P is the pressure in atm (0.201 atm)
  • V is the volume in litres (1 L)
  • n is the number of moles of the gas
  • R is the ideal gas constant (0.0821 L·atm/(K·mol))
  • T is the temperature in Kelvin (25°C + 273.15 = 298.15 K)

Rearranging the formula to find n:

n=PVRTn = \frac{PV}{RT}

Substituting the values:

n=(0.201atm)(1L)(0.0821L\cdotpatm/(K\cdotpmol))(298.15K)n = \frac{(0.201 \, \text{atm}) (1 \, \text{L})}{(0.0821 \, \text{L·atm/(K·mol)}) (298.15 \, \text{K})}

Calculating this gives:

n=0.20124.4660.0082 molesn = \frac{0.201}{24.466} \approx 0.0082 \text{ moles}

Step 2

Calculate the concentration in moles per litre

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Answer

Since we have the number of moles (0.0082 moles) and the volume of the flask (1 litre), the concentration of oxygen is:

Concentration=nV=0.0082moles1L=0.0082mol/L\text{Concentration} = \frac{n}{V} = \frac{0.0082 \, \text{moles}}{1 \, \text{L}} = 0.0082 \, \text{mol/L}

Step 3

Select the correct answer

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Answer

Based on the calculated concentration of 0.0082 mol/L, the correct answer from the options provided is:

D. 0.0082

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