Photo AI

A coal-fired power station is used to generate electricity - VCE - SSCE Chemistry - Question 2 - 2022 - Paper 1

Question icon

Question 2

A-coal-fired-power-station-is-used-to-generate-electricity-VCE-SSCE Chemistry-Question 2-2022-Paper 1.png

A coal-fired power station is used to generate electricity. Carbon dioxide, CO₂, gas is produced as part of the process. a. Carbon capture and storage is one option... show full transcript

Worked Solution & Example Answer:A coal-fired power station is used to generate electricity - VCE - SSCE Chemistry - Question 2 - 2022 - Paper 1

Step 1

Calculate the pressure in kilopascals

96%

114 rated

Answer

To determine the pressure of the CO₂ gas in the tank, we can use the ideal gas law, given by the formula:

PV=nRTPV = nRT

Where:

  • PP is the pressure in pascals (Pa)
  • VV is the volume in liters (L)
  • nn is the number of moles of gas
  • RR is the ideal gas constant, approximately 8.314 rac{J}{K imes mol}
  • TT is the temperature in Kelvin (K)

First, we need to convert the given temperature from Celsius to Kelvin:

T=28.0°C+273.15=301.15KT = 28.0 °C + 273.15 = 301.15 K

Inserting the values into the equation, we convert the volume from liters to cubic meters for proper SI units:

V=20000.0L=20000.0imes103m3=20m3V = 20000.0 L = 20000.0 imes 10^{-3} m^3 = 20 m^3

Now substituting the known values into the ideal gas law:

P=nRTVP = \frac{nRT}{V}

Substituting:

  • n=5.17×104moln = 5.17 \times 10^{4} mol
  • R=8.314JK×mol=8.314Pam3KmolR = 8.314 \frac{J}{K \times mol} = 8.314 \frac{Pa \cdot m^3}{K \cdot mol}
  • T=301.15KT = 301.15 K
  • V=20m3V = 20 m^3

Calculation: P=(5.17×104mol)(8.314Pam3Kmol)(301.15K)20m3P = \frac{(5.17 \times 10^{4} mol)(8.314 \frac{Pa \cdot m^3}{K \cdot mol})(301.15 K)}{20 m^3}

P=1295731.6320=64786.58PaP = \frac{1295731.63}{20} = 64786.58 Pa

Since 1 kPa = 1000 Pa, converting this to kilopascals gives: P=64786.58Pa1000=64.79kPaP = \frac{64786.58 Pa}{1000} = 64.79 kPa

Thus, the pressure in the tank is approximately 64.79 kPa.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;