When hydrochloric acid is added to aluminium sulfide, the highly toxic gas hydrogen sulfide is evolved. The equation for this reaction is: $$\text{Al}_2\text{S}_3(s) + 6\text{HCl}(aq) \rightarrow 2\text{AlCl}_3(aq) + 3\text{H}_2\text{S}(g)$$ If excess hydrochloric acid is added to 0.200 mol of aluminium sulfide, then the volume of hydrogen sulfide produced at standard laboratory conditions (SLC) will be: - 1.63 L - 4.90 L - 7.35 L - 14.7 L

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When hydrochloric acid is added to aluminium sulfide, the highly toxic gas hydrogen sulfide is evolved - VCE - SSCE Chemistry - Question 8 - 2014 - Paper 1

Question 8

When hydrochloric acid is added to aluminium sulfide, the highly toxic gas hydrogen sulfide is evolved. The equation for this reaction is: $$\text{Al}_2\text{S}_3(s... show full transcript

Worked Solution & Example Answer:When hydrochloric acid is added to aluminium sulfide, the highly toxic gas hydrogen sulfide is evolved - VCE - SSCE Chemistry - Question 8 - 2014 - Paper 1

Step 1

Calculate Moles of Hydrogen Sulfide Produced

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Answer

According to the balanced chemical equation, 1 mole of aluminium sulfide produces 3 moles of hydrogen sulfide.

Therefore, 0.200 mol of aluminium sulfide will produce:

$3 \times 0.200 \text{ mol} = 0.600 \text{ mol of } \text{H}_2\text{S}$

Step 2

Convert Moles to Volume at SLC

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Answer

At standard laboratory conditions (SLC), 1 mole of gas occupies approximately 24.0 L. Thus, the volume of hydrogen sulfide produced can be calculated as follows:

$\text{Volume} = \text{moles} \times \text{molar volume} = 0.600 \text{ mol} \times 24.0 \text{ L/mol} = 14.4 \text{ L}$

Step 3

Select the Closest Option

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Answer

The calculated volume of 14.4 L rounds to the closest option provided, which is:

14.7 L

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