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Myrcene is a naturally occurring compound found in the leaves of bay trees - VCE - SSCE Chemistry - Question 4 - 2009 - Paper 1

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Myrcene is a naturally occurring compound found in the leaves of bay trees. It is known to be a polysaturated hydrocarbon. It can react with hydrogen to produce a sa... show full transcript

Worked Solution & Example Answer:Myrcene is a naturally occurring compound found in the leaves of bay trees - VCE - SSCE Chemistry - Question 4 - 2009 - Paper 1

Step 1

What type of reaction has occurred between the myrcene and hydrogen?

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Answer

The reaction that has occurred between myrcene and hydrogen is an addition reaction. Specifically, it is a hydrogenation reaction, where hydrogen is added to the myrcene to convert it into a saturated alkane.

Step 2

Calculate the amount, in moles, of hydrogen reacting.

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Answer

To calculate the amount of hydrogen gas reacting, we can use the ideal gas law. The formula is:

n=PVRTn = \frac{PV}{RT}

Where:

  • PP = pressure in kPa = 105.0 kPa
  • VV = volume in liters = 510 mL = 0.510 L
  • RR = ideal gas constant = 8.31 L·kPa/(K·mol)
  • TT = temperature in Kelvin = 20.0°C + 273 = 293 K

Substituting the values:

n=105.0×0.5108.31×293=0.0220 moln = \frac{105.0 \times 0.510}{8.31 \times 293} = 0.0220 \text{ mol}

Step 3

Calculate the mass of C₁₀H₂₂ produced in the reaction.

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The molar mass of C₁₀H₂₂ can be calculated as follows:

  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol

Thus, the molar mass of C₁₀H₂₂ is:

10×12.01+22×1.008=142.28 g/mol10 \times 12.01 + 22 \times 1.008 = 142.28 \text{ g/mol}

Now, to find the mass produced, we use the number of moles of C₁₀H₂₂ produced:

Mass = Moles × Molar Mass

Given that 0.0220 moles of C₁₀H₂₂ were produced:

Mass=0.0220×142.28=3.14 g\text{Mass} = 0.0220 \times 142.28 = 3.14 \text{ g}

Step 4

Determine the number of double bonds in each molecule of myrcene.

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Answer

Each molecule of myrcene has three double bonds. This is because when myrcene undergoes hydrogenation, three molecules of H₂ are added, saturating its three double bonds to convert it into C₁₀H₂₂.

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