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One litre of air at atmospheric pressure and 25°C is held in a flask - VCE - SSCE Chemistry - Question 17 - 2005 - Paper 1

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One litre of air at atmospheric pressure and 25°C is held in a flask. The pressure of oxygen in the flask is 0.201 atm (20.4 kPa). The concentration of oxygen in th... show full transcript

Worked Solution & Example Answer:One litre of air at atmospheric pressure and 25°C is held in a flask - VCE - SSCE Chemistry - Question 17 - 2005 - Paper 1

Step 1

Calculate the number of moles of oxygen

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Answer

To find the concentration of oxygen, we first need to use the ideal gas law, which is given by the equation:

PV=nRTPV = nRT

Where:

  • PP is the pressure of the gas (in atm),
  • VV is the volume of the gas (in liters),
  • nn is the number of moles of the gas,
  • RR is the ideal gas constant (0.0821 L·atm/(K·mol)), and
  • TT is the temperature (in Kelvin).
  1. Convert the temperature from Celsius to Kelvin:
    T=25+273.15=298.15extKT = 25 + 273.15 = 298.15 ext{ K}
  2. Rearranging for the number of moles:
    n=PVRTn = \frac{PV}{RT}
  3. Substitute in the known values:
    n=(0.201extatm)(1extL)(0.0821extLatm/(Kmol))(298.15extK)n = \frac{(0.201 ext{ atm})(1 ext{ L})}{(0.0821 ext{ L·atm/(K·mol)})(298.15 ext{ K})}
    n0.0082extmoln \approx 0.0082 ext{ mol}

Step 2

Calculate the concentration in moles per liter

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Answer

Since the volume of the gas sampled is 1 liter, the concentration (CC) in mole per liter is given by:

C=nVC = \frac{n}{V}

Substituting the values:

C=0.0082extmol1extL=0.0082extmol/LC = \frac{0.0082 ext{ mol}}{1 ext{ L}} = 0.0082 ext{ mol/L}

Thus, the concentration of oxygen in the flask is 0.0082 mol/L, which corresponds to option D.

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