1 L of octane has a mass of 703 g at SLC - VCE - SSCE Chemistry - Question 22 - 2021 - Paper 1

The energy produced by 1 L of octane (703 g) can be found using the heat of combustion of octane. The standard heat of combustion for octane is approximately 47.9 MJ/kg. First, we convert the grams to kilograms:

$$703 \text{ g} = 0.703 \text{ kg}$$

Now, we calculate the total energy produced by 1 L of octane:

$$E_{produced} = 0.703 \text{ kg} \times 47.9 \text{ MJ/kg} \approx 33.59 \text{ MJ}$$

Now, we know the total energy required (2112 MJ) and the energy produced per liter of octane (approximately 33.59 MJ). To find the volume of octane needed, we divide the total energy by the energy produced by one liter:

$$V = \frac{E_{total}}{E_{produced}} = \frac{2112 \text{ MJ}}{33.59 \text{ MJ/L}} \approx 62.7 \text{ L}$$

Thus, the volume of octane required is approximately 62.7 L.