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The percentage purity of powdered, impure magnesium sulfate, MgSO₄, can be determined by gravimetric analysis - VCE - SSCE Chemistry - Question 1 - 2008 - Paper 1

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The percentage purity of powdered, impure magnesium sulfate, MgSO₄, can be determined by gravimetric analysis. Shown below is the method used in one such analysis. ... show full transcript

Worked Solution & Example Answer:The percentage purity of powdered, impure magnesium sulfate, MgSO₄, can be determined by gravimetric analysis - VCE - SSCE Chemistry - Question 1 - 2008 - Paper 1

Step 1

Different volumes of 0.100 M BaCl₂(aq) are added to six separate 20.00 mL samples of this solution.

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Answer

To determine the percentage purity of MgSO₄, measure the volume of 0.100 M BaCl₂ used for each 20.00 mL sample. Each volume added should lead to the precipitation of a corresponding mass of BaSO₄. The mass of BaSO₄ can be calculated from its relation with the original sulfate concentration.

Step 2

The equation for the reaction is Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)

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Using stoichiometry, relate the moles of BaSO₄ precipitated back to the moles of MgSO₄ in the original solution. For example, if 2.00 g of BaSO₄ precipitate is recovered, convert this mass to moles:

nBaSO4=massmBaSO4=2.00g233.39g/mol0.00857moln_{BaSO₄} = \frac{mass}{m_{BaSO₄}} = \frac{2.00 g}{233.39 g/mol} \approx 0.00857 mol

Since the reaction is 1:1, this also represents the moles of SO₄²⁻ precipitated, which in turn equals the moles of MgSO₄ in the initial sample.

Step 3

The precipitate from each sample is filtered, rinsed with de-ionised water and then dried to constant mass.

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Answer

Calculate the concentration of the original MgSO₄ solution based on the total volume and concentration of BaCl₂ added. Finally, to find the percentage purity, use the formula:

Percentage Purity=(mass of pure MgSO4mass of impure sample)×100\text{Percentage Purity} = \left( \frac{\text{mass of pure MgSO}_4}{\text{mass of impure sample}} \right) \times 100

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