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The molecule HOCH₂CH₂CH₂COOH (molar mass = 104 g mol⁻¹) forms a polymer in which the average polymer molecule contains 1000 monomer units - VCE - SSCE Chemistry - Question 20 - 2006 - Paper 1

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The molecule HOCH₂CH₂CH₂COOH (molar mass = 104 g mol⁻¹) forms a polymer in which the average polymer molecule contains 1000 monomer units. The approximate molar mas... show full transcript

Worked Solution & Example Answer:The molecule HOCH₂CH₂CH₂COOH (molar mass = 104 g mol⁻¹) forms a polymer in which the average polymer molecule contains 1000 monomer units - VCE - SSCE Chemistry - Question 20 - 2006 - Paper 1

Step 1

Calculate the total molar mass of the polymer

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Answer

To find the total molar mass of the polymer, we multiply the molar mass of the monomer by the number of monomer units in the polymer.

Given:

  • Molar mass of the monomer = 104 g mol⁻¹
  • Number of monomer units = 1000

The formula for the molar mass of the polymer is:

extTotalMolarMass=extMolarMassofMonomerimesextNumberofMonomerUnits=104extgmol1imes1000=104000extgmol1 ext{Total Molar Mass} = ext{Molar Mass of Monomer} imes ext{Number of Monomer Units} = 104 ext{ g mol}^{-1} imes 1000 = 104000 ext{ g mol}^{-1}

Step 2

Choose the correct answer from the options provided

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Answer

Based on our calculation, the total molar mass of the polymer is 104000 g mol⁻¹. The correct answer from the options provided is:

D. 104 000

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