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A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar - VCE - SSCE Chemistry - Question 19 - 2021 - Paper 1

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Question 19

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A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar. A 3.959 g sample of the musli bar w... show full transcript

Worked Solution & Example Answer:A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar - VCE - SSCE Chemistry - Question 19 - 2021 - Paper 1

Step 1

Calculate the total energy released

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Answer

To find the total energy released during the combustion, we can use the formula:

Q=C×ΔTQ = C \times \Delta T

where:

  • QQ is the heat energy (in joules),
  • CC is the calibration factor of the calorimeter (4780 J °C⁻¹),
  • ΔT\Delta T is the change in temperature (16.7 °C).

Plugging in the values:

Q=4780×16.7=79766 JQ = 4780 \times 16.7 = 79766 \text{ J}

Step 2

Calculate the energy content per gram

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Answer

Next, to find the energy content per gram, we divide the total energy released by the mass of the musli bar:

Energy content per gram=Qmass\text{Energy content per gram} = \frac{Q}{\text{mass}}

Here, the mass is 3.959 g:

Energy content per gram=797663.95920124.07extJg1\text{Energy content per gram} = \frac{79766}{3.959} \approx 20124.07 ext{ J g}^{-1}

Thus, converting to scientific notation:

20124.07extJg1=2.02×104extJg120124.07 ext{ J g}^{-1} = 2.02 \times 10^4 ext{ J g}^{-1}

Step 3

Select the correct answer from options

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Answer

Comparing the calculated value with the provided options, the closest match is:

B. 2.02 × 10⁶ J g⁻¹

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