A fuel cell is set up based on the oxidation of methane - VCE - SSCE Chemistry - Question 6 - 2004 - Paper 1
Question 6
A fuel cell is set up based on the oxidation of methane. Again, the equation for the anode half reaction is
$$ CH_4(g) + 2H_2O(l) \rightarrow CO_2(g) + 8H^+(aq) + 8... show full transcript
Worked Solution & Example Answer:A fuel cell is set up based on the oxidation of methane - VCE - SSCE Chemistry - Question 6 - 2004 - Paper 1
Step 1
Calculate the charge from one mole of electrons
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Answer
The oxidation of one mole of methane produces 8 moles of electrons, as indicated by the balanced half reaction. The total charge (Q) is calculated using Faraday's constant, which is approximately 96485 C/mol. Therefore, the charge from the oxidation of one mole of methane is:
Q=n×F
where:
n = number of moles of electrons = 8
F = Faraday's constant = 96485 C/mol
Calculating:
Q=8×96485 C/mol≈771880 C
This result can be rounded to 8×105 C.
Step 2
Choose the closest option
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Answer
From the calculated value of approximately 8×105 C, the closest answer option is C: 8×105.
