Below are the half-equations for the lead-acid accumulator cell - VCE - SSCE Chemistry - Question 25 - 2023 - Paper 1
Question 25
Below are the half-equations for the lead-acid accumulator cell. The lead-acid accumulator cell can operate as an electrolytic cell.
$$ ext{PbSO}_4 (s) + ext{H}^+(... show full transcript
Worked Solution & Example Answer:Below are the half-equations for the lead-acid accumulator cell - VCE - SSCE Chemistry - Question 25 - 2023 - Paper 1
Step 1
A. H^+ ions react at the cathode.
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Answer
In galvanic cells, reduction occurs at the cathode. The half-equation shows that H^+ ions react to form Pb, which is a reduction reaction.
Step 2
B. H^+ ions react at the anode.
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Answer
This statement is incorrect for a galvanic cell, as oxidation occurs at the anode.
Step 3
C. H^+ ions react at the cathode. HSO_4^- ions react at both electrodes.
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Answer
This is the correct explanation. In the galvanic cell, H^+ ions are reduced at the cathode, while HSO_4^- ions participate in reactions at both electrodes.
Step 4
D. HSO_4^- ions are produced at both electrodes.
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This statement is also incorrect, as HSO_4^- ions do not get produced at both electrodes during the reactions.
