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A small electric vehicle is powered by rechargeable lead-acid car batteries - VCE - SSCE Chemistry - Question 4 - 2004 - Paper 1

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A small electric vehicle is powered by rechargeable lead-acid car batteries. The energy that drives the vehicle comes from the cell reaction Pb(s) + PbO2(s) + 2H2SO... show full transcript

Worked Solution & Example Answer:A small electric vehicle is powered by rechargeable lead-acid car batteries - VCE - SSCE Chemistry - Question 4 - 2004 - Paper 1

Step 1

Write the equation for the cathode half reaction.

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Answer

The cathode half-reaction involves the reduction of lead dioxide (PbO2) in the presence of sulfuric acid (H2SO4). The balanced equation for the cathode half reaction is:

PbO2(s)+2H+(aq)+2ePbSO4(s)+H2O(l)PbO_2(s) + 2H^+(aq) + 2e^- → PbSO_4(s) + H_2O(l)

Step 2

How much energy, in kJ, is used by the vehicle in travelling for 2.5 hours?

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Answer

To calculate the energy consumed while travelling, we first convert the travel time into seconds:

2.5exthours=2.5imes3600=9000extseconds2.5 ext{ hours} = 2.5 imes 3600 = 9000 ext{ seconds}

With an average energy consumption of 1.0 kJ/s, the total energy used is:

extEnergy=extPowerimesextTime=1.0extkJ/simes9000exts=9000extkJ ext{Energy} = ext{Power} imes ext{Time} = 1.0 ext{ kJ/s} imes 9000 ext{ s} = 9000 ext{ kJ}

Step 3

Write the equation for the overall chemical reaction that occurs when the battery is being recharged.

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Answer

The overall reaction for recharging the battery involves reversing the initial reaction. The equation is:

2PbSO4(s)+2H2O(l)Pb(s)+PbO2(s)+2H2SO4(aq)2PbSO_4(s) + 2H_2O(l) → Pb(s) + PbO_2(s) + 2H_2SO_4(aq)

Step 4

What voltage should be used to recharge each battery?

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The voltage required to recharge the batteries must be higher than the nominal voltage of 12 V. Therefore, a suitable recharging voltage would be:

extRechargingvoltage>12extV ext{Recharging voltage} > 12 ext{ V}

Typically, a voltage of at least 13.8 V is often used to ensure proper charging.

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