Photo AI

Different metal ion (aq)/metal (s) half-cells are combined with an In³⁺(aq)/In(s) half-cell to create a galvanic cell at SLC, as shown in the diagram below - VCE - SSCE Chemistry - Question 26 - 2021 - Paper 1

Question icon

Question 26

Different-metal-ion-(aq)/metal-(s)-half-cells-are-combined-with-an-In³⁺(aq)/In(s)-half-cell-to-create-a-galvanic-cell-at-SLC,-as-shown-in-the-diagram-below-VCE-SSCE Chemistry-Question 26-2021-Paper 1.png

Different metal ion (aq)/metal (s) half-cells are combined with an In³⁺(aq)/In(s) half-cell to create a galvanic cell at SLC, as shown in the diagram below. The equa... show full transcript

Worked Solution & Example Answer:Different metal ion (aq)/metal (s) half-cells are combined with an In³⁺(aq)/In(s) half-cell to create a galvanic cell at SLC, as shown in the diagram below - VCE - SSCE Chemistry - Question 26 - 2021 - Paper 1

Step 1

Which half-cell combinations produce the highest voltage?

96%

114 rated

Answer

To determine which half-cell combinations produce the highest voltage when paired with the In³⁺(aq)/In(s) half-cell, we need to compare their standard electrode potentials with the given half-cell potential of 0.34 V-0.34 \text{ V}. The more positive the electrode potential of a half-cell is, the higher the voltage will be when combined with the In(s) electrode. We consider the standard reduction potentials for each metal ion given in the options.

Step 2

Order the options based on electrode potentials.

99%

104 rated

Answer

By analyzing the standard electrode potentials for the metals listed in option C:

  1. Cu²⁺(aq) + 2e⁻ ⇌ Cu(s) with E=+0.34 VE^\circ = +0.34 \text{ V}
  2. Pb²⁺(aq) + 2e⁻ ⇌ Pb(s) with E=0.13 VE^\circ = -0.13 \text{ V}
  3. Zn²⁺(aq) + 2e⁻ ⇌ Zn(s) with E=0.76 VE^\circ = -0.76 \text{ V}

This results in a positive cell potential when combined with In(s), making it the highest voltage option. Thus, option C is the correct answer.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;