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Naturally occurring copper exists as two isotopes, 63Cu and 65Cu - VCE - SSCE Chemistry - Question 16 - 2004 - Paper 1

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Naturally occurring copper exists as two isotopes, 63Cu and 65Cu. The relative atomic mass of copper is 63.6. The ratio of 63Cu to 65Cu in natural copper is approxim... show full transcript

Worked Solution & Example Answer:Naturally occurring copper exists as two isotopes, 63Cu and 65Cu - VCE - SSCE Chemistry - Question 16 - 2004 - Paper 1

Step 1

Calculate the contribution of each isotope

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Answer

Given the relative atomic mass of copper is 63.6, we can denote the fractions of 63Cu and 65Cu as x and y, respectively.

Using the equation for the average atomic mass: x×63+y×65=63.6x \times 63 + y \times 65 = 63.6

Since these are the only two isotopes, we also have: x+y=1x + y = 1

Now, substituting y with (1 - x) gives: x×63+(1x)×65=63.6x \times 63 + (1 - x) \times 65 = 63.6

Step 2

Solve the equations

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Answer

Expanding that, we get: 63x+6565x=63.663x + 65 - 65x = 63.6 Combining like terms gives: 2x+65=63.6-2x + 65 = 63.6 Thus: 2x=63.665-2x = 63.6 - 65 2x=1.4-2x = -1.4 x=0.7x = 0.7

Now substituting back to find y: y=1x=10.7=0.3y = 1 - x = 1 - 0.7 = 0.3

Step 3

Determine the ratio

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Answer

Now that we have x and y, we find the ratio of 63Cu to 65Cu: Ratio=xy=0.70.3=73\text{Ratio} = \frac{x}{y} = \frac{0.7}{0.3} = \frac{7}{3} This simplifies to approximately 3:1.

Step 4

Final answer

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Answer

Thus, the ratio of 63Cu to 65Cu in natural copper is approximately 3:1, which corresponds to option D.

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