Hydrogen and chlorine react according to the equation
$$H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$$
3 mole of H_2 and 2 mole of Cl_2 are placed in a vessel and sealed - VCE - SSCE Chemistry - Question 10 - 2005 - Paper 1
Question 10
Hydrogen and chlorine react according to the equation
$$H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$$
3 mole of H_2 and 2 mole of Cl_2 are placed in a vessel and sealed. ... show full transcript
Worked Solution & Example Answer:Hydrogen and chlorine react according to the equation
$$H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$$
3 mole of H_2 and 2 mole of Cl_2 are placed in a vessel and sealed - VCE - SSCE Chemistry - Question 10 - 2005 - Paper 1
Step 1
Identify the Limiting Reactant
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Answer
From the chemical equation, 1 mole of H₂ reacts with 1 mole of Cl₂ to produce 2 moles of HCl. Therefore, for every 1 mole of H₂, we need 1 mole of Cl₂. Since we have 3 moles of H₂ and 2 moles of Cl₂, Cl₂ is the limiting reactant.
Step 2
Calculate the Amount of HCl Produced
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Answer
Using the limiting reactant (Cl₂), we can calculate the amount of HCl produced. 2 moles of Cl₂ will produce 4 moles of HCl (because the ratio of Cl₂ to HCl is 1:2). Thus, when the reaction is complete, we will have 4 moles of HCl.
Step 3
Calculate Remaining Reactants
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Answer
Since 2 moles of Cl₂ react with 2 moles of H₂, we initially had 3 moles of H₂. After the reaction, 1 mole of H₂ will remain because 2 moles were consumed.
Step 4
Final Answer
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Answer
When the reaction is complete, the vessel will contain 4 moles of HCl and 1 mole of H₂, which corresponds to option D.
