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How does diluting a 0.1 M solution of lactic acid, HC₃H₅O₃, change its pH and percentage ionisation? A - VCE - SSCE Chemistry - Question 20 - 2016 - Paper 1

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How does diluting a 0.1 M solution of lactic acid, HC₃H₅O₃, change its pH and percentage ionisation? A. increase decrease B. increase increase C. decrease increase ... show full transcript

Worked Solution & Example Answer:How does diluting a 0.1 M solution of lactic acid, HC₃H₅O₃, change its pH and percentage ionisation? A - VCE - SSCE Chemistry - Question 20 - 2016 - Paper 1

Step 1

pH Response to Dilution

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Answer

When a weak acid like lactic acid is diluted, the concentration of hydrogen ions ([H+][H^+]) in the solution decreases. The pH of a solution is given by the formula:

pH=extlog([H+])pH = - ext{log}([H^+])

Therefore, as the concentration decreases, the pH increases.

Step 2

Percentage Ionisation Response to Dilution

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Answer

The percentage ionisation of a weak acid increases when diluted because the weak acid is less concentrated, allowing more of it to ionise compared to the undiluted state. This is expressed as:

ext{Percentage Ionisation} = rac{[A^-]}{[HA]} imes 100

where [A][A^-] is the concentration of the ionised form and [HA][HA] is the concentration of the un-ionised form. As the denominator decreases due to dilution, the percentage of ionisation becomes larger.

Step 3

Final Answer Selection

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Answer

From the analysis, we conclude that diluting the lactic acid solution results in an increase in pH and an increase in percentage ionisation. Therefore, the correct option is B: increase, increase.

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