Consider the following chemical equations:
2NO2(g) → 2NO(g) + O2(g) ΔHf = +14 kJ mol⁻¹
NO(g) + CO(g) → CO2(g) + NO(g) ΔHf = -226 kJ mol⁻¹
2NO(g) → N2O4(g) ΔHf = -57 kJ mol⁻¹
N2(g) + O2(g) → 2NO(g) ΔHf = +181 kJ mol⁻¹
Which one of the following graphs is consistent with the chemical equations above? - VCE - SSCE Chemistry - Question 18 - 2021 - Paper 1
Question 18
Consider the following chemical equations:
2NO2(g) → 2NO(g) + O2(g) ΔHf = +14 kJ mol⁻¹
NO(g) + CO(g) → CO2(g) + NO(g) ΔHf = -226 kJ mol⁻¹
2NO(g) → N2O4(g) ΔHf = ... show full transcript
Worked Solution & Example Answer:Consider the following chemical equations:
2NO2(g) → 2NO(g) + O2(g) ΔHf = +14 kJ mol⁻¹
NO(g) + CO(g) → CO2(g) + NO(g) ΔHf = -226 kJ mol⁻¹
2NO(g) → N2O4(g) ΔHf = -57 kJ mol⁻¹
N2(g) + O2(g) → 2NO(g) ΔHf = +181 kJ mol⁻¹
Which one of the following graphs is consistent with the chemical equations above? - VCE - SSCE Chemistry - Question 18 - 2021 - Paper 1
Step 1
A. Analyze the first reaction: 2NO2(g) → 2NO(g) + O2(g)
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Answer
This reaction has a positive enthalpy change (+14 kJ mol⁻¹), indicating it is endothermic. The graph should show an increase in enthalpy from the reactants to the products.
Step 2
B. Analyze the second reaction: NO(g) + CO(g) → CO2(g) + NO(g)
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Answer
This reaction has a significantly negative enthalpy change (-226 kJ mol⁻¹), indicating it is highly exothermic. The graph should show a notable dip in enthalpy as the reaction progresses.
Step 3
C. Analyze the third reaction: 2NO(g) → N2O4(g)
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Answer
This reaction is exothermic with a negative enthalpy change (-57 kJ mol⁻¹), suggesting that the graph should show a decrease in enthalpy upon formation of the products.
Step 4
D. Analyze the fourth reaction: N2(g) + O2(g) → 2NO(g)
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Answer
This reaction has a positive enthalpy change (+181 kJ mol⁻¹), indicating an endothermic process. The graph will depict an increase in enthalpy from reactants to products.
Step 5
E. Determine the best graph: Graph C
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Answer
Given that the endothermic and exothermic reactions reflect a combination of enthalpic changes, graph C, which shows one endothermic and one exothermic process, is consistent with the chemical equations. Thus, the answer is C.