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Two galvanic cells were constructed under standard conditions in an experiment to determine the relative positions in the electrochemical series of the standard electrode potential, $E^\circ$, for the following reactions - VCE - SSCE Chemistry - Question 10 - 2011 - Paper 1

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Two galvanic cells were constructed under standard conditions in an experiment to determine the relative positions in the electrochemical series of the standard elec... show full transcript

Worked Solution & Example Answer:Two galvanic cells were constructed under standard conditions in an experiment to determine the relative positions in the electrochemical series of the standard electrode potential, $E^\circ$, for the following reactions - VCE - SSCE Chemistry - Question 10 - 2011 - Paper 1

Step 1

Determine the standard electrode potentials

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Answer

To solve this problem, we need to analyze the given half-reactions to understand their standard electrode potentials relative to each other. The more positive the electrode potential, the stronger the oxidizing agent. Here are the half-reactions:

  1. Ag(NH3_3)2++e_2^+ + e^- \rightarrow Ag + 2NH3_3 (This is an oxidation reaction with a higher potential)
  2. Ag(s) \rightarrow Ag++e^+ + e^- (A standard reference used in this context)
  3. Ag(CN)2+e_2^- + e^- \rightarrow Ag + 2CN^- (This half-reaction will be compared against the others)

Based on the standard electrode potentials often known or provided in reference tables, we conclude the following relationship among them.

Step 2

Rank the electrode potentials

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Answer

From the analysis, the order from highest to lowest electrode potential is:

  • E3E_3 > E1E_1 > E2E_2. So, we find that option C (E3E_3, E1E_1, E2E_2) is the correct answer.

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