A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar. A 3.959 g sample of the musli bar was combusted in the calorimeter and the temperature of the water rose by 16.7 °C. The calibration factor of the calorimeter was previously determined to be 4780 J °C⁻¹. The energy content of the musli bar is A. 3.51 × 10⁵ J g⁻¹ B. 2.02 × 10⁶ J g⁻¹ C. 1.13 × 10⁵ J g⁻¹ D. 7.25 × 10⁶ J g⁻¹

Photo AI

A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar - VCE - SSCE Chemistry - Question 19 - 2021 - Paper 1

Question 19

A-food-chemist-conducted-an-experiment-in-a-bomb-calorimeter-to-determine-the-energy-content,-in-joules-per-gram,-of-a-musli-bar-VCE-SSCE Chemistry-Question 19-2021-Paper 1.png

A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar. A 3.959 g sample of the musli bar w... show full transcript

Worked Solution & Example Answer:A food chemist conducted an experiment in a bomb calorimeter to determine the energy content, in joules per gram, of a musli bar - VCE - SSCE Chemistry - Question 19 - 2021 - Paper 1

Step 1

Calculate the energy released during combustion

96%

114 rated

Answer

To find the energy released from the combustion of the musli bar, we can use the formula:

$Q = C \times \Delta T$

where:

$Q$ is the heat energy released (in joules).
$C$ is the calibration factor of the calorimeter (4780 J °C⁻¹).
$\Delta T$ is the change in temperature (16.7 °C).

Substituting the values, we get:

$Q = 4780 \times 16.7 = 79826 J$

Step 2

Calculate the energy content per gram

99%

104 rated

Answer

Next, to find the energy content per gram, we divide the total energy released by the mass of the musli bar sample:

$\text{Energy content} = \frac{Q}{m}$

where:

$m$ is the mass of the musli bar (3.959 g).

Thus,

$\text{Energy content} = \frac{79826}{3.959} \approx 20181 J g^{-1}$

Converting this to scientific notation, we have:

$\approx 2.02 \times 10^{4} J g^{-1}$

Upon checking the options given, we find:

B. 2.02 × 10⁶ J g⁻¹ is the correct energy content.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;