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A sample of the insecticide dichlorodiphenyltrichloroethane (DDT), C14H9Cl5, was found to contain 0.120 g of carbon - VCE - SSCE Chemistry - Question 3 - 2010 - Paper 1

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A sample of the insecticide dichlorodiphenyltrichloroethane (DDT), C14H9Cl5, was found to contain 0.120 g of carbon. What mass of chlorine was present in the sample... show full transcript

Worked Solution & Example Answer:A sample of the insecticide dichlorodiphenyltrichloroethane (DDT), C14H9Cl5, was found to contain 0.120 g of carbon - VCE - SSCE Chemistry - Question 3 - 2010 - Paper 1

Step 1

Calculate the molar mass of DDT

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Answer

To find the mass of chlorine in the sample, we first need to determine the molar mass of DDT. The molecular formula of DDT is C14H9Cl5. We calculate the molar mass by summing the atomic masses of all the atoms:

  • Carbon (C): 14 atoms × 12.01 g/mol = 168.14 g/mol
  • Hydrogen (H): 9 atoms × 1.01 g/mol = 9.09 g/mol
  • Chlorine (Cl): 5 atoms × 35.45 g/mol = 177.25 g/mol

The total molar mass of DDT is:

MDDT=168.14+9.09+177.25=354.48extg/molM_{DDT} = 168.14 + 9.09 + 177.25 = 354.48 ext{ g/mol}

Step 2

Determine the number of moles of carbon in the sample

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Answer

Next, we calculate the number of moles of carbon in the sample using the mass of carbon provided (0.120 g):

n_{C} = rac{0.120 ext{ g}}{12.01 ext{ g/mol}} = 0.00998 ext{ moles}

Step 3

Determine the number of moles of chlorine in DDT

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Answer

Since the ratio of carbon to chlorine in DDT is 14:5, we can find the moles of chlorine in DDT using the moles of carbon calculated earlier:

n_{Cl} = n_{C} imes rac{5}{14}

Thus,

n_{Cl} = 0.00998 imes rac{5}{14} = 0.00357 ext{ moles}

Step 4

Calculate the mass of chlorine in the sample

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Answer

Finally, we can find the mass of chlorine using the number of moles calculated and the molar mass of chlorine:

extMassofCl=nClimes35.45extg/mol=0.00357imes35.45extg/mol=0.127extg ext{Mass of } Cl = n_{Cl} imes 35.45 ext{ g/mol} = 0.00357 imes 35.45 ext{ g/mol} = 0.127 ext{ g}

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