Draw the structural formula for an isomer of 1-bromopentane that contains a chiral carbon and circle this chiral carbon. - VCE - SSCE Chemistry - Question 6 - 2021 - Paper 1

To obtain an isomer of 1-bromopentane that contains a chiral carbon, we can consider 2-bromopentane as an option. The structural formula for 2-bromopentane can be drawn as follows:

   Br
    |
H3C-CH-CH2-CH2
    |   
   H  H   

In this structure, the chiral carbon is the central carbon (next to the Br) that has four different substituents: a bromine (Br), a methyl group (CH3), a hydrogen (H), and an ethyl group (CH2-CH3). Circle this carbon to indicate its chiral nature.

To circle the chiral carbon, you can represent it as:

   Br
    |
H3C-C(Chiral) -CH2-CH2
    |   
   H  H   

where (Chiral) indicates that this carbon is the chiral center.