1 F is equivalent to the charge on 1 mol of electrons - VCE - SSCE Chemistry - Question 20 - 2021 - Paper 1

Using Faraday's constant, which is approximately 96485 C/mol for the charge of 1 mole of electrons, we calculate the moles of electrons:

$n = \frac{Q}{F} = \frac{320\, C}{96485\, C/mol} \approx 0.00331 \text{ mol}$

The molar mass of nickel (Ni) is approximately 58.69 g/mol. The mass can be calculated using:

$m = n \times M = 0.00331\, mol \times 58.69\, g/mol \approx 0.194 \text{ g}$

However, since the question lists answers in g × 10⁴, we convert this value:

$0.194 \text{ g} \times 10^4 = 1.94 \times 10^4 ext{ g}$ This rounds to approximately 1.95 × 10⁴ g, which corresponds to answer choice B.