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Consider the reaction $$CH_2=CH-CH=CH_2 + Br_2 \rightarrow Z$$ Z would be represented by A - VCE - SSCE Chemistry - Question 6 - 2003 - Paper 1

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Consider the reaction $$CH_2=CH-CH=CH_2 + Br_2 \rightarrow Z$$ Z would be represented by A. $CH_3CHBrCHBrCH_3$ B. $CH_2BrCH(Br)CH_3$ C. $CH_2BrCH(CH_2)CH_2Br$... show full transcript

Worked Solution & Example Answer:Consider the reaction $$CH_2=CH-CH=CH_2 + Br_2 \rightarrow Z$$ Z would be represented by A - VCE - SSCE Chemistry - Question 6 - 2003 - Paper 1

Step 1

Identify the Reaction Product

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Answer

In the given reaction, an alkene, specifically 1,3-butadiene (CH2=CHCH=CH2CH_2=CH-CH=CH_2), reacts with bromine (Br2Br_2). This is an electrophilic addition reaction where the double bonds in the alkene will react with bromine, leading to the formation of dibrominated products.

Step 2

Determine the Structure of Z

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Answer

The reaction will add bromine across the double bonds. The most likely product Z will contain bromine atoms on adjacent carbon atoms as they get added to the former double bonds. Considering the provided options:

  • Option A (CH3CHBrCHBrCH3CH_3CHBrCHBrCH_3) shows bromine on the second and third carbon, which is possible.
  • Option B (CH2BrCH(Br)CH3CH_2BrCH(Br)CH_3) and Option C (CH2BrCH(CH2)CH2BrCH_2BrCH(CH_2)CH_2Br) introduce complications in positional isomerism but can also be possible structures.
  • Option D (CH3BrCH2CH2BrCH_3BrCH_2CH_2Br) suggests the bromine is placed at the terminal positions which does not reflect the correct intermediate stability.

After evaluating the structures, A (CH3CHBrCHBrCH3CH_3CHBrCHBrCH_3) emerges as the only plausible product because it conforms with expected stereochemistry and stability.

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