The nutritional information for one medium serving (124 g) of sweet potato is provided in the table below - VCE - SSCE Chemistry - Question 5 - 2021 - Paper 1

To calculate the energy contained in one medium serving of sweet potato, we can use the energy values of the macronutrients. The energy (in kJ) provided by each nutrient can be calculated using the following formula:

• Energy from protein:

  $2.0 ext{ g} imes 17 ext{ kJ/g} = 34 ext{ kJ}$

• Energy from fat:

  $3.0 ext{ g} imes 37 ext{ kJ/g} = 111 ext{ kJ}$

• Energy from carbohydrates:

  $18.7 ext{ g} imes 16 ext{ kJ/g} = 299.2 ext{ kJ}$

Adding these values together gives:

$34 ext{ kJ} + 111 ext{ kJ} + 299.2 ext{ kJ} = 444.2 ext{ kJ}$

Thus, the energy contained in one medium serving of sweet potato is approximately 444 kJ.