Brønsted–Lowry Acid-Base Theory Simplified Revision Notes for SSCE HSC Chemistry
Revision notes with simplified explanations to understand Brønsted–Lowry Acid-Base Theory quickly and effectively.
Learn about Brønsted–Lowry Theory for your SSCE Chemistry Exam. This Revision Note includes a summary of Brønsted–Lowry Theory for easy recall in your Chemistry exam
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Brønsted–Lowry Acid-Base Theory
Introduction to the Brønsted–Lowry Theory
Brønsted–Lowry Acid: A substance that donates protons (hydrogen ions/H⁺).
Brønsted–Lowry Base: A substance that accepts protons.
This theory provides insight into reactions beyond aqueous environments, extending its relevance to non-aqueous reactions.
infoNote
Brønsted–Lowry Acid: A donor of hydrogen ions/H⁺.
Brønsted–Lowry Base: A proton acceptor.
Historical Context
Arrhenius Theory: Concentrates solely on aqueous solutions with acids releasing H⁺ and bases releasing OH⁻.
Lewis Theory: Involves reactions with electron pairs.
Brønsted–Lowry Theory: Broadens the scope to include reactions in solvents like ammonia and methanol.
chatImportant
The Brønsted–Lowry theory extends earlier models, playing a crucial role in contemporary chemistry.
Base Dissociation and Dissociation Constants
Base Dissociation in Water
Base Dissociation: The process by which bases dissociate in water to yield hydroxide ions (OH⁻).
Example: Ammonia (NH₃) reacting with water:
NH3+H2O⇌NH4++OH−
infoNote
Base Dissociation: The process through which bases release hydroxide ions in water.
Define Kb and pKb
Kb (Base Dissociation Constant): Represents the strength of a base in an aqueous solution.
A higher Kb value indicates a stronger base.
infoNote
Kb: Quantifies the degree to which a base dissociates into ions in water.
pKb: The logarithmic form of Kb, where a lower pKb signifies stronger bases.
pKb=−log10(Kb)
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pKb Conversion: Facilitates easier numerical comparison of base strengths.
Mathematical Representation
Formula:
Kb=[B][OH−][HB+]
Calculation Example for NH₃:
Initial concentrations: [NH₄⁺] = 0.01 M, [OH⁻] = 0.01 M, [NH₃] = 0.1 M.
Calculation:
Kb=0.10.01×0.01=1.0×10−3
Comparing Kb and Ka
Understand their relationship in chemical equilibria.
Ammonia (base):NH3+H2O⇌NH4++OH−
Acetic acid (acid):CH3COOH+H2O⇌CH3COO−+H+
Exploring Neutralisation Reactions
Neutralisation Basics
Neutralisation reactions: Processes where acids and bases produce water and salt.
Equivalence Point: The stage at which the moles of H⁺ equal the moles of OH⁻, achieving complete neutralisation.
Example Process:
HCl dissociates into H⁺ and Cl⁻.
NaOH dissociates into Na⁺ and OH⁻.
H⁺ and OH⁻ form water, while Na⁺ and Cl⁻ form salt (NaCl).
Visualising and Analysing Neutralisation
Titration Curves: Display pH variations during neutralisation.
pH Indicators: Phenolphthalein changes from pink to clear upon neutralisation.
Knowledge Check
Exercise 1: Calculate Kb for ammonia, [NH₄⁺] = 0.01 M, [OH⁻] = 0.01 M, [NH₃] = 0.1 M.
Solution: Using the formula Kb=[NH3][OH−][NH4+], we substitute the known values:
Kb=0.10.01×0.01=0.10.0001=1.0×10−3
Exercise 2: Given Kb=1.8×10−5, find the pKb.
Solution: Using the formula pKb=−log10(Kb):
pKb=−log10(1.8×10−5)=−(−4.7447)=4.74
Glossary
Kb (Base Dissociation Constant): A measure of a base's capability to dissociate in water.
pKb: A logarithmic representation to compare base strength.
Dissociation: The breakdown of a compound into ions in solution.
Resonance: The distribution of electron density that stabilises a molecule.
Substituents: Atoms or groups attached to a molecule affecting its chemical characteristics.
chatImportant
Comprehending Kb and pKb values is vital for predicting base behaviour in solutions. Strong bases are characterised by high Kb and low pKb values.
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