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Brønsted–Lowry Acid-Base Theory Simplified Revision Notes

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Brønsted–Lowry Acid-Base Theory

Introduction to the Brønsted–Lowry Theory

  • Brønsted–Lowry Acid: A substance that donates protons (hydrogen ions/H⁺).
  • Brønsted–Lowry Base: A substance that accepts protons.

This theory provides insight into reactions beyond aqueous environments, extending its relevance to non-aqueous reactions.

infoNote

Brønsted–Lowry Acid: A donor of hydrogen ions/H⁺. Brønsted–Lowry Base: A proton acceptor.

Historical Context

  • Arrhenius Theory: Concentrates solely on aqueous solutions with acids releasing H⁺ and bases releasing OH⁻.
  • Lewis Theory: Involves reactions with electron pairs.
  • Brønsted–Lowry Theory: Broadens the scope to include reactions in solvents like ammonia and methanol.
chatImportant

The Brønsted–Lowry theory extends earlier models, playing a crucial role in contemporary chemistry.

Timeline graphic highlighting the development of acid-base theories, focusing on the shift introduced by Brønsted and Lowry.

Base Dissociation and Dissociation Constants

Base Dissociation in Water

  • Base Dissociation: The process by which bases dissociate in water to yield hydroxide ions (OH⁻).
  • Example: Ammonia (NH₃) reacting with water: NH3+H2ONH4++OH\mathrm{NH}_3 + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{NH}_4^+ + \mathrm{OH}^-
infoNote

Base Dissociation: The process through which bases release hydroxide ions in water.

Define Kb and pKb

  • Kb (Base Dissociation Constant): Represents the strength of a base in an aqueous solution.
    • A higher Kb value indicates a stronger base.
infoNote

Kb: Quantifies the degree to which a base dissociates into ions in water.

  • pKb: The logarithmic form of Kb, where a lower pKb signifies stronger bases.

pKb=log10(Kb)\mathrm{pK}_b = -\log_{10}(K_b)

infoNote

pKb Conversion: Facilitates easier numerical comparison of base strengths.

A table comparing common bases with their Kb and pKb values, designed to help students understand dissociation trends.

Mathematical Representation

  • Formula: Kb=[OH][HB+][B]K_b = \frac{[\mathrm{OH}^-][\mathrm{HB}^+]}{[\mathrm{B}]}
  • Calculation Example for NH₃:
    • Initial concentrations: [NH₄⁺] = 0.01 M, [OH⁻] = 0.01 M, [NH₃] = 0.1 M.
    • Calculation: Kb=0.01×0.010.1=1.0×103K_b = \frac{0.01 \times 0.01}{0.1} = 1.0 \times 10^{-3}

Comparing Kb and Ka

  • Understand their relationship in chemical equilibria.
  • Ammonia (base): NH3+H2ONH4++OH\mathrm{NH}_3 + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{NH}_4^+ + \mathrm{OH}^-
  • Acetic acid (acid): CH3COOH+H2OCH3COO+H+\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}^+

Exploring Neutralisation Reactions

Neutralisation Basics

  • Neutralisation reactions: Processes where acids and bases produce water and salt.
  • Equivalence Point: The stage at which the moles of H⁺ equal the moles of OH⁻, achieving complete neutralisation.
  • Example Process:
    • HCl dissociates into H⁺ and Cl⁻.
    • NaOH dissociates into Na⁺ and OH⁻.
    • H⁺ and OH⁻ form water, while Na⁺ and Cl⁻ form salt (NaCl).

Visualising and Analysing Neutralisation

  • Titration Curves: Display pH variations during neutralisation.

    Diagram of a titration curve showing the path of pH changes during neutralisation, with labeled sections like initial pH, buffering region, and equivalence point.

  • pH Indicators: Phenolphthalein changes from pink to clear upon neutralisation.

    Illustration showing the colour change in a pH indicator as neutralisation progresses.

Knowledge Check

  • Exercise 1: Calculate Kb for ammonia, [NH₄⁺] = 0.01 M, [OH⁻] = 0.01 M, [NH₃] = 0.1 M. Solution: Using the formula Kb=[OH][NH4+][NH3]K_b = \frac{[\mathrm{OH}^-][\mathrm{NH}_4^+]}{[\mathrm{NH}_3]}, we substitute the known values: Kb=0.01×0.010.1=0.00010.1=1.0×103K_b = \frac{0.01 \times 0.01}{0.1} = \frac{0.0001}{0.1} = 1.0 \times 10^{-3}

  • Exercise 2: Given Kb=1.8×105K_b = 1.8 \times 10^{-5}, find the pKb\mathrm{pK}_b. Solution: Using the formula pKb=log10(Kb)\mathrm{pK}_b = -\log_{10}(K_b): pKb=log10(1.8×105)=(4.7447)=4.74\mathrm{pK}_b = -\log_{10}(1.8 \times 10^{-5}) = -(-4.7447) = 4.74

Glossary

  • Kb (Base Dissociation Constant): A measure of a base's capability to dissociate in water.
  • pKb: A logarithmic representation to compare base strength.
  • Dissociation: The breakdown of a compound into ions in solution.
  • Resonance: The distribution of electron density that stabilises a molecule.
  • Substituents: Atoms or groups attached to a molecule affecting its chemical characteristics.
chatImportant

Comprehending Kb and pKb values is vital for predicting base behaviour in solutions. Strong bases are characterised by high Kb and low pKb values.

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