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Understanding solubility equilibrium is essential for grasping how ionic compounds, such as NaCl, react with solvents to form solutions. This equilibrium is achieved when the rate of solute dissolution matches the rate of precipitation, resulting in a stable concentration of dissolved ions.
Dynamic equilibrium is key to understanding chemical reactions and predicting how chemical systems stabilise even as conditions change.
Dissolution is observed in daily activities, such as dissolving salt in water, and is vital to numerous chemical processes.
Understanding dissolution is fundamental for explaining everyday processes and chemical interactions crucial in cooking, cleaning, and industrial applications.
When NaCl is introduced to water, it dissociates into ions facilitated by water's polar nature, creating hydration shells.
Ion-Water Interaction Steps:
Solubility: Defined as the capacity of a substance to dissolve, influenced by ion-dipole interactions.
Key Insight: Dissolution is a chemical reaction, not merely the mixing of substances.
Examples:
Increased thermal energy impacts the dissolution process—this is related to enthalpy changes due to energy transfer.
Henry's Law: The solubility of a gas is directly proportional to the pressure of the gas above the liquid. Formula:
Thermodynamics: The study of energy transformations in processes such as dissolution.
Entropy (ΔS): Corresponds to the increased disorder as dissolving occurs.
Equation:
Example: If ΔH = 10 kJ/mol, ΔS = 50 J/mol⋅K, and T = 298 K, then:
A negative ΔG indicates spontaneous dissolution.
Solubility Product Constant (Ksp): Measures the solubility of sparingly soluble ionic compounds. Higher Ksp values denote greater solubility.
Derivation of Ksp Formula
For ionic compound AB:
Exam Tip: Predict equilibrium shifts due to ion addition employing Le Chatelier's principle.
Problem: For a salt AB with Ksp = 4.0 × 10⁻⁵, calculate its solubility in mol/L.
Solution:
Write the equilibrium equation: AB(s) ⇌ A⁺(aq) + B⁻(aq)
Let's call the solubility 's' in mol/L:
Write the Ksp expression: Ksp = [A⁺][B⁻] = s × s = s²
Solve for s: s² = 4.0 × 10⁻⁵ s = √(4.0 × 10⁻⁵) = 6.3 × 10⁻³ mol/L
Therefore, the solubility of AB is 6.3 × 10⁻³ mol/L.
Problem: Determine if precipitation will occur when 100 mL of 0.02 M AgNO₃ is mixed with 200 mL of 0.01 M NaCl. (Ksp for AgCl = 1.8 × 10⁻¹⁰)
Solution:
Calculate diluted concentrations after mixing:
Calculate the ion product Q: Q = [Ag⁺][Cl⁻] = 0.0067 × 0.0067 = 4.5 × 10⁻⁵
Compare Q with Ksp: Q (4.5 × 10⁻⁵) > Ksp (1.8 × 10⁻¹⁰)
Since Q > Ksp, precipitation will occur.
Integrated Effects: Solubility is influenced by temperature, pressure, and common ions acting together.
Case Study in Desalination:
Misconception Example: Solutes do not vanish; they maintain equilibrium in solution.
Grasping solubility equilibrium is fundamental for delving into more intricate chemical scenarios, spanning from pharmaceuticals to ecological systems. Utilise the provided diagrams and examples to visualise and reinforce these concepts.
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