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Discriminant Analysis Simplified Revision Notes

Revision notes with simplified explanations to understand Discriminant Analysis quickly and effectively.

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Discriminant Analysis

Introduction and Purpose

The discriminant: Δ=b24ac\Delta = b^2 - 4ac is a key mathematical concept used to determine the type of roots in quadratic equations. Grasping its importance is vital for recognising:

  • Real and distinct roots
  • One real repeated root
  • Complex conjugate roots

Discriminant Importance

  • Assists in identifying the type and quantity of solutions.
  • Crucial in physics and engineering for addressing complex real-world scenarios.
infoNote

Definitions:

  • Quadratic Equation: ax2+bx+c=0ax^2 + bx + c = 0, employed to determine roots (xx-values) where the equation equals zero.
  • Discriminant: Δ=b24ac\Delta = b^2 - 4ac, assesses the root type in quadratic equations.

Role in Determining Roots

  • Nature of Roots based on the discriminant Δ\Delta:
    • Δ>0\Delta > 0: Two distinct real roots.
    • Δ=0\Delta = 0: One real repeated root.
    • Δ<0\Delta < 0: Two complex conjugate roots.

Visual Learning Enhancements

  • Utilise diagrams for educational purposes:

    • Parabolas intersecting the x-axis to demonstrate the discriminant's impact.

    Graphical representation of a quadratic equation on a coordinate plane, showing the effect of changing coefficients on the parabola and discriminant.

Calculation and Baseline Understanding

Example Problems

  • Calculating Δ\Delta
    • Example: x24x+3=0x^2 - 4x + 3 = 0
      • Identify coefficients: a=1a = 1, b=4b = -4, c=3c = 3.
      • Calculate: (4)24×1×3=1612=4(-4)^2 - 4 \times 1 \times 3 = 16 - 12 = 4.
      • Two distinct real roots since Δ=4>0\Delta = 4 > 0.
  • Additional Examples:
    • x22x+1=0x^2 - 2x + 1 = 0: Δ=0\Delta = 0 (one repeated root).
    • x2+x+1=0x^2 + x + 1 = 0: Δ=3\Delta = -3 (complex roots).

Worked Examples

  1. Case Δ>0\Delta > 0:

    • Example: x25x+6=0x^2 - 5x + 6 = 0
      • First, identify the coefficients: a=1a = 1, b=5b = -5, c=6c = 6
      • Calculate the discriminant: Δ=(5)24×1×6=2524=1\Delta = (-5)^2 - 4 \times 1 \times 6 = 25 - 24 = 1
      • Since Δ>0\Delta > 0, there are two distinct real roots
      • Using the quadratic formula: x=5±12=5±12x = \frac{5 \pm \sqrt{1}}{2} = \frac{5 \pm 1}{2}
      • Therefore, roots are x=2x = 2 and x=3x = 3 A graph of a parabola intersecting the x-axis at two points, illustrating the case \Delta > 0.
  2. Case Δ=0\Delta = 0:

    • Example: x24x+4=0x^2 - 4x + 4 = 0
      • First, identify the coefficients: a=1a = 1, b=4b = -4, c=4c = 4
      • Calculate the discriminant: Δ=(4)24×1×4=1616=0\Delta = (-4)^2 - 4 \times 1 \times 4 = 16 - 16 = 0
      • Since Δ=0\Delta = 0, there is one repeated root
      • Using the quadratic formula: x=42=2x = \frac{4}{2} = 2
      • Therefore, the repeated root is x=2x = 2 A graph of a parabola tangent to the x-axis at one point, illustrating the case \Delta = 0.
  3. Case Δ<0\Delta < 0:

    • Example: x2+x+1=0x^2 + x + 1 = 0
      • First, identify the coefficients: a=1a = 1, b=1b = 1, c=1c = 1
      • Calculate the discriminant: Δ=124×1×1=14=3\Delta = 1^2 - 4 \times 1 \times 1 = 1 - 4 = -3
      • Since Δ<0\Delta < 0, there are complex conjugate roots
      • Using the quadratic formula: x=1±32=1±i32x = \frac{-1 \pm \sqrt{-3}}{2} = \frac{-1 \pm i\sqrt{3}}{2}
      • Therefore, the roots are complex conjugates A graph of a parabola that does not intersect the x-axis, illustrating the case \Delta < 0.

Common Misconceptions

  • Error Sources: Incorrect calculation or misinterpretation of the discriminant.
chatImportant

Correction Strategies:

  • Re-evaluate calculations for precision.
  • Ensure logical coherence in equation solving.
  • Confirm correct interpretation of the discriminant's result.

Practice Problems with Solutions

  1. Compute Δ\Delta for x27x+10=0x^2 - 7x + 10 = 0.

    • Solution: a=1a = 1, b=7b = -7, c=10c = 10
    • Δ=(7)24×1×10=4940=9\Delta = (-7)^2 - 4 \times 1 \times 10 = 49 - 40 = 9
    • Since Δ>0\Delta > 0, there are two distinct real roots.
  2. Determine Δ\Delta for x26x+9=0x^2 - 6x + 9 = 0.

    • Solution: a=1a = 1, b=6b = -6, c=9c = 9
    • Δ=(6)24×1×9=3636=0\Delta = (-6)^2 - 4 \times 1 \times 9 = 36 - 36 = 0
    • Since Δ=0\Delta = 0, there is one repeated root, which is x=3x = 3.
  3. Evaluate Δ\Delta for x2+x+2=0x^2 + x + 2 = 0.

    • Solution: a=1a = 1, b=1b = 1, c=2c = 2
    • Δ=124×1×2=18=7\Delta = 1^2 - 4 \times 1 \times 2 = 1 - 8 = -7
    • Since Δ<0\Delta < 0, there are complex conjugate roots.

Application Examples

  • Projectile Paths: Employ discriminants to predict intersections with targets.
    • Outcome: Lack of real intersection results in missing the target.
  • Engineering: Apply checks in evaluating material stress for project viability.

Conclusion

Comprehending discriminants facilitates the prediction of root types, enabling thorough preparation for exams and practical applications in disciplines such as physics and engineering.

Graphical illustration showing how different parameter values impact parabolas to generate distinct roots.

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