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Describe the structure and function of the nucleus - AQA - A-Level Biology - Question 1 - 2022 - Paper 1

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Describe the structure and function of the nucleus. The nucleus is a membrane-bound organelle found in eukaryotic cells. Its structure includes: - A nuclear envelop... show full transcript

Worked Solution & Example Answer:Describe the structure and function of the nucleus - AQA - A-Level Biology - Question 1 - 2022 - Paper 1

Step 1

Name the main polymer that forms the following cell walls.

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Answer

Plant cell wall: Cellulose Fungal cell wall: Chitin

Step 2

Suggest one reason the scientists used biomass instead of the number of individuals of each plant species when collecting data to measure diversity.

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Answer

One reason is that individual organisms could not be easily identified or separated, making it difficult to collect accurate counts of distinct species.

Step 3

Use this equation to calculate the index of diversity for the data in Table 1.

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Answer

To calculate the index of diversity, we first determine the total shoot biomass: Total shoot biomass = 2 + 4 + 5 + 7 + 15 + 36 + 51 = 120 g/m². Next, we apply the index diversity equation:

d=1i=1n(niN)2d = 1 - \sum_{i=1}^n \left( \frac{n_i}{N} \right)^2 Where nin_i represents the shoot biomass of each species and NN is the total shoot biomass. Calculating the necessary ratios:

  • For Poa compressa: (2120)2=0.00027778(\frac{2}{120})^2 = 0.00027778
  • For Achillea millefolium: (4120)2=0.00069444(\frac{4}{120})^2 = 0.00069444
  • For Aster cordifolius: (5120)2=0.00173611(\frac{5}{120})^2 = 0.00173611
  • For Aster nova-angliae: (7120)2=0.00347222(\frac{7}{120})^2 = 0.00347222
  • For Chrysanthemum leucanthemum: (15120)2=0.015625(\frac{15}{120})^2 = 0.015625
  • For Daucus carota: (36120)2=0.090000(\frac{36}{120})^2 = 0.090000
  • For Fragaria virginiana: (51120)2=0.220225(\frac{51}{120})^2 = 0.220225

Total = $0.00027778 + 0.00069444 + 0.00173611 + 0.00347222 + 0.015625 + 0.090000 + 0.220225 = 0.331 Now, substituting into the equation: d = 1 - 0.331 = 0.669

Step 4

Suggest and explain how the plant species index of diversity would be different in these areas previously used to grow crops.

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Answer

In areas previously used to grow crops, plant biodiversity is likely to be lower compared to land not used for cropping. This occurs because farming often reduces the variety of plant species, as it typically involves monoculture practices that favor the growth of a single crop, decreasing overall diversity. Consequently, the index of biodiversity may reflect this reduced diversity, resulting in a lower value when compared to areas with natural ecosystems, where a wider variety of species coexists.

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