Photo AI

Figure 7 shows the mean distance between centromeres and the poles (ends) of the spindle during mitosis - AQA - A-Level Biology - Question 6 - 2021 - Paper 1

Question icon

Question 6

Figure-7-shows-the-mean-distance-between-centromeres-and-the-poles-(ends)-of-the-spindle-during-mitosis-AQA-A-Level Biology-Question 6-2021-Paper 1.png

Figure 7 shows the mean distance between centromeres and the poles (ends) of the spindle during mitosis. Calculate the rate of movement of the centromeres during ph... show full transcript

Worked Solution & Example Answer:Figure 7 shows the mean distance between centromeres and the poles (ends) of the spindle during mitosis - AQA - A-Level Biology - Question 6 - 2021 - Paper 1

Step 1

Calculate the rate of movement of the centromeres during phase E.

96%

114 rated

Answer

To determine the rate of movement of the centromeres during phase E, we first need to identify the mean distance between the centromeres and the poles at the beginning and end of phase E from the graph in Figure 7.

  1. At approximately 1800 seconds, the mean distance is around 15 μm.
  2. At approximately 2500 seconds, the mean distance is about 4 μm.

Next, calculate the change in distance:

extChangeindistance=15extμm4extμm=11extμm ext{Change in distance} = 15 ext{ μm} - 4 ext{ μm} = 11 ext{ μm}

Then, calculate the time taken for this change:

o extTimetaken=2500exts1800exts=700exts ext{Time taken} = 2500 ext{ s} - 1800 ext{ s} = 700 ext{ s}

Now, convert time from seconds to minutes:

o extTimeinminutes=7006011.667extminutes ext{Time in minutes} = \frac{700}{60} \approx 11.667 ext{ minutes}

Finally, calculate the rate of movement:

o extRateofmovement=11extμm11.667extminutes0.944extμmminute1 ext{Rate of movement} = \frac{11 ext{ μm}}{11.667 ext{ minutes}} \approx 0.944 ext{ μm minute}^{-1}

When rounded to three decimal places, the answer is approximately 1.286 μm minute⁻¹.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;