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Figure 4 shows a diagram of a Pacinian corpuscle - AQA - A-Level Biology - Question 2 - 2022 - Paper 3

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Figure 4 shows a diagram of a Pacinian corpuscle. Figure 4 Name the structures labelled P, Q and R shown in Figure 4. P Q R Two students (A and B) investigated r... show full transcript

Worked Solution & Example Answer:Figure 4 shows a diagram of a Pacinian corpuscle - AQA - A-Level Biology - Question 2 - 2022 - Paper 3

Step 1

Name the structures labelled P, Q and R shown in Figure 4.

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Answer

The structures labelled in Figure 4 are:

  • P: Capsule
  • Q: Nerve ending
  • R: Lamellae

Step 2

Calculate the percentage uncertainty in the measurement of Trial 1 in Table 3.

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Answer

To calculate the percentage uncertainty, we use the formula:

ext{Percentage Uncertainty} = rac{ ext{Uncertainty}}{ ext{Measured Value}} imes 100

In this case, if we assume an uncertainty of ±1 mm (common for measuring tools), the calculation is:

ext{Percentage Uncertainty} = rac{1}{79} imes 100 ightarrow 1.27\%

Thus, the correct option is 1.27%.

Step 3

Suggest one explanation for the value recorded in Trial 3.

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Answer

One possible explanation for the value recorded in Trial 3 (10 mm) could be that the student had not fully prepared to catch the ruler, thus resulting in a delayed reaction time.

Step 4

Use Table 3 and Table 4 to calculate the mean speed of nerve impulse transmission.

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Answer

To calculate the mean speed of nerve impulse transmission, we use the formula:

ext{Speed} = rac{ ext{Distance}}{ ext{Time}}

From Table 3, we take the distance for Trial 1, which is 79 mm. Using Table 4, the corresponding time for 79 mm is 120 ms (from interpolation or estimation).

First, convert the distance to meters: 79 ext{ mm} = 0.079 ext{ m}

And convert the time to seconds: 120 ext{ ms} = 0.120 ext{ s}

Now we can calculate the speed:

ext{Speed} = rac{0.079 ext{ m}}{0.120 ext{ s}} = 0.6583 ext{ m s}^{-1}

So the mean speed of nerve impulse transmission is approximately 0.658 m s⁻¹.

Step 5

Suggest three reasons why, in this investigation, the estimated speed of student A’s impulse transmission was less than 76.2 m s⁻¹.

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Answer

  1. The pathway involved might have included sensory receptors that were not directly analyzed in this investigation, leading to slower transmission speeds.

  2. There could have been variability in the student's physiological response, such as fatigue or distraction, affecting their reaction time.

  3. The method of measuring the response time might not accurately correlate with the speed of nerve impulse transmission due to factors such as synaptic delays.

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