Photo AI

Figure 1 shows the growth pattern followed by a type of tumour - AQA - A-Level Biology - Question 6 - 2019 - Paper 3

Question icon

Question 6

Figure-1-shows-the-growth-pattern-followed-by-a-type-of-tumour-AQA-A-Level Biology-Question 6-2019-Paper 3.png

Figure 1 shows the growth pattern followed by a type of tumour. You will need to use the ‘#’ button on your calculator. Figure 2 can also be used to calculate the ... show full transcript

Worked Solution & Example Answer:Figure 1 shows the growth pattern followed by a type of tumour - AQA - A-Level Biology - Question 6 - 2019 - Paper 3

Step 1

Calculate Percentage of Maximum Growth

96%

114 rated

Answer

To calculate the percentage of maximum growth, first identify the maximum size of the tumour from the graph (Figure 1). Suppose the maximum size reached is around 10 units. If at a certain time the tumour size is 5 units, the percentage can be calculated as follows:

extPercentageGrowth=(Current SizeMaximum Size)×100=(510)×100=50%. ext{Percentage Growth} = \left( \frac{\text{Current Size}}{\text{Maximum Size}} \right) \times 100 = \left( \frac{5}{10} \right) \times 100 = 50\%.

Step 2

Calculate Tumour Size

99%

104 rated

Answer

Using the data provided in the figures, if the growth of the tumour described can be estimated to follow the indications of dibasic acid concentration, you would use the relevant formula from your calculator, inputting the required values from the provided equations in Figure 2.

Step 3

Suggest How Tricet Does Cell Division

96%

101 rated

Answer

Tricet acts as a competitive inhibitor of enzymes, specifically targeting dihydrofolate reductase which is responsible for DNA synthesis. By inhibiting this enzyme, Tricet reduces the availability of nucleotides necessary for DNA replication, leading to a reduction in cell division. Fewer enzyme-substrate complexes form, which decreases cellular proliferation.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;