Photo AI
A two-step preparation of propylamine is shown - AQA - A-Level Chemistry - Question 30 - 2021 - Paper 3
Question 30
A two-step preparation of propylamine is shown. bromoethane → X → propylamine What is X? A CH₃CH₂CH₂NH₂ B CH₃CH₂CN C CH₃CH₂CH₂Br D CH₃CH₂NH₂
Worked Solution & Example Answer:A two-step preparation of propylamine is shown - AQA - A-Level Chemistry - Question 30 - 2021 - Paper 3
Step 1
What is X?
Answer
To find compound X in the two-step preparation of propylamine, we need to identify the intermediate compound formed from bromoethane that will ultimately yield propylamine.
- Understanding the Reaction: Propylamine (C₃H₉NH₂) is formed from an alkyl halide (bromoethane, C₂H₅Br) and a suitable nucleophile.
- Identifying the Intermediate: In the first step, treatment of bromoethane with a nucleophile (such as a cyanide ion, CN⁻) would lead to the formation of propionitrile (C₃H₅CN).
- Final Transformation: The nitrile can then be converted to the corresponding amine through hydrolysis and reduction steps.
Based on the options provided, the structure corresponding to propionitrile is:
B CH₃CH₂CN, which is the correct answer for X.