This question is about 2-methylbut-1-ene - AQA - A-Level Chemistry - Question 3 - 2022 - Paper 2
Question 3
This question is about 2-methylbut-1-ene.
1. Name the mechanism for the reaction of 2-methylbut-1-ene with concentrated sulfuric acid.
Outline the mechanism for thi... show full transcript
Worked Solution & Example Answer:This question is about 2-methylbut-1-ene - AQA - A-Level Chemistry - Question 3 - 2022 - Paper 2
Step 1
Name the mechanism for the reaction of 2-methylbut-1-ene with concentrated sulfuric acid.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The mechanism involved in this reaction is called Electrophilic Addition. In this process, the concentrated sulfuric acid acts as an electrophile, attacking the double bond of 2-methylbut-1-ene.
Step 2
Outline the mechanism for this reaction to form the major product.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The sulfuric acid donates a proton (H+) to the double bond, leading to the formation of a carbocation.
The carbocation rearranges to form a more stable secondary carbocation, if possible.
The bisulfate ion (HSO4-) then acts as a nucleophile, attacking the positively charged carbon atom of the carbocation.
This reaction results in the formation of the alkyl hydrogensulfate as the major product.
Step 3
Draw the structure of the minor product formed in the reaction in Question 03.1
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The minor product formed in the reaction is 2-methylbutyl hydrogen sulfate. Its structure can be represented as:
CH3
|
CH3-C-OSO3H
|
CH2
|
CH3
Step 4
Explain why this is the minor product.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This is considered the minor product because it is formed from a less stable carbocation. The pathway leading to the major product involves the formation of a more stable carbocation due to rearrangement, making it more favorable than this alternative pathway.
Step 5
Draw the skeletal formula of a functional group isomer of 2-methylbut-1-ene.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
A functional group isomer of 2-methylbut-1-ene is 2-methylbutan-1-ol. It can be represented as:
CH3
|
CH3-C-CH2-CH2OH
|
CH3
Step 6
State the type of polymerisation.
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The type of polymerisation for 2-methylbut-1-ene is Addition Polymerisation.
Step 7
Draw the repeating unit for the polymer formed.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The repeating unit for the polymer formed can be represented as: