Use the Data Booklet to help you answer this question - AQA - A-Level Chemistry - Question 6 - 2017 - Paper 2
Question 6
Use the Data Booklet to help you answer this question.
This question is about amino acids and peptide (amide) links.
1. Draw the structure of the zwitterion formed... show full transcript
Worked Solution & Example Answer:Use the Data Booklet to help you answer this question - AQA - A-Level Chemistry - Question 6 - 2017 - Paper 2
Step 1
Draw the structure of the zwitterion formed by phenylalanine.
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Answer
The zwitterion of phenylalanine shows the amino group (−NH3+) protonated and the carboxyl group (−COO−) deprotonated. The structure can be represented as:
NH_3^+
|
H2N-C-COO^-
|
C6H5
Where the carbon chain includes the phenyl group.
Step 2
Draw the structure of serine at high pH.
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At high pH, serine has its amino group protonated and the hydroxyl group (−OH) remains. The structure can be represented as:
NH_2
|
H2N-C-COO^-
|
CH2
|
OH
Here, the carboxylic acid is in its deprotonated form (−COO−).
Step 3
Draw the structures of both dipeptides formed when phenylalanine reacts with serine.
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Answer
The two dipeptides formed can be illustrated as:
Phenylalanine-Serine (Phe-Ser):
NH_2
|
H2N-C-CO(NH)-C-COO^-
|
CH2
|
OH
Serine-Phenylalanine (Ser-Phe):
NH_2
|
H2N-C-CO(NH)-C6H5
|
CH2
|
COO^-
In both structures, the amide link is denoted by the bond between the carbonyl carbon and the amino nitrogen.
Step 4
Name and outline a mechanism for the reaction between CH3CH2COCl and CH3CH2NH2.
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Answer
The mechanism is known as nucleophilic addition-elimination. In this reaction:
The nucleophile (ethanamine, CH3CH2NH2) attacks the carbonyl carbon of the acyl chloride (CH3CH2COCl).
A tetrahedral intermediate is formed.
The chloride ion is eliminated leading to the formation of the amide:
CH3CH2C(O)NHCH2CH3
The IUPAC name of the organic product is N-ethylpropanamide.