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A two-step preparation of propylamine is shown - AQA - A-Level Chemistry - Question 30 - 2021 - Paper 3
Question 30
A two-step preparation of propylamine is shown. bromoethane → X → propylamine What is X? A) CH₃CH₂CH₂NH₂ B) CH₃CH₂CN C) CH₃CH₂CH₂Br D) CH₃CH₂NH₂
Worked Solution & Example Answer:A two-step preparation of propylamine is shown - AQA - A-Level Chemistry - Question 30 - 2021 - Paper 3
Step 1
What is X?
Answer
To determine the compound X in the two-step preparation of propylamine from bromoethane, we need to investigate the reactions involved.
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Understanding the Target Compound: The target compound is propylamine, which has the structure CH₃CH₂CH₂NH₂. To form this compound, we need a precursor that can introduce the NH₂ group.
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Analyzing the Options:
- Option A: CH₃CH₂CH₂NH₂ is propylamine itself and cannot be X.
- Option B: CH₃CH₂CN is propionitrile, which can be converted to propylamine via a reduction reaction.
- Option C: CH₃CH₂CH₂Br is bromo-propyl and doesn't help introduce the amine group.
- Option D: CH₃CH₂NH₂ is ethylamine, which is not suitable as an intermediate here.
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Conclusion: The compound X must be CH₃CH₂CN, making it the correct answer for the formation of propylamine.