Which statement is correct about both 2-methylbutan-1-ol and 2-methylbutan-2-ol?
A They can be formed by alkaline hydrolysis of esters - AQA - A-Level Chemistry - Question 11 - 2018 - Paper 3
Question 11
Which statement is correct about both 2-methylbutan-1-ol and 2-methylbutan-2-ol?
A They can be formed by alkaline hydrolysis of esters.
B They can be oxidised by... show full transcript
Worked Solution & Example Answer:Which statement is correct about both 2-methylbutan-1-ol and 2-methylbutan-2-ol?
A They can be formed by alkaline hydrolysis of esters - AQA - A-Level Chemistry - Question 11 - 2018 - Paper 3
Step 1
A They can be formed by alkaline hydrolysis of esters.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is incorrect because 2-methylbutan-1-ol and 2-methylbutan-2-ol are primary and secondary alcohols, respectively, and cannot directly arise from alkaline hydrolysis of esters.
Step 2
B They can be oxidised by reaction with acidified potassium dichromate(VI).
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is incorrect because while 2-methylbutan-1-ol (a primary alcohol) can be oxidized, 2-methylbutan-2-ol (a secondary alcohol) can also be oxidized, making the statement misleading as it does not apply equally to both.
Step 3
C They can be formed by hydration of 2-methylbut-2-ene.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is correct because both 2-methylbutan-1-ol and 2-methylbutan-2-ol can be synthesized through the hydration of 2-methylbut-2-ene.
Step 4
D They have four peaks in their 13C NMR spectra.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is also correct. Both compounds, being different structural isomers of the same molecular formula, exhibit distinct chemical environments for their carbon atoms, resulting in unique sets of peaks in their 13C NMR spectra.
