Coconut oil contains a triester with three identical R groups - AQA - A-Level Chemistry - Question 1 - 2021 - Paper 2
Question 1
Coconut oil contains a triester with three identical R groups.
This triester reacts with potassium hydroxide.
RCOO–CH₂ + 3KOH → 3RCOOK +
RCOO–CH +
RCOO–CH₂
1. Co... show full transcript
Worked Solution & Example Answer:Coconut oil contains a triester with three identical R groups - AQA - A-Level Chemistry - Question 1 - 2021 - Paper 2
Step 1
Complete the equation by drawing the structure of the other product of this reaction in the box.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The other product of this reaction is the potassium salt of the fatty acid, which can be represented as:
K+RCOO−
This compound is a potassium carboxylate salt.
Step 2
Name the type of compound shown by the formula RCOOK
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The compound RCOOK is a potassium carboxylate salt.
Step 3
Give one use for this type of compound.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
One use for potassium carboxylate salts is in the production of soap, where they act as surfactants.
Step 4
Deduce the value of n in CH₃(CH₂)n.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To determine the value of n:
The molar mass of R, from the triester, can be calculated as follows:
M = 638 g/mol
R has a structure of CH₃(CH₂)n, where the mass contribution is:
extC=12extg/mol,H=1extg/mol
The approximate mass of the alkyl group R:
12+2n+1=12+2n+1
Therefore, we get:
638=3(12+2n+1)+58ext(weightofKandOatoms)
Solving gives n = 14.
Step 5
Calculate the percentage by mass of the triester (M=638.0) in the coconut oil.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the percentage by mass:
Calculate the amount of KOH reacted:
Moles of KOH = mass / molar mass = 0.421 g / 56.1 g/mol = 0.00749 mol
Mass = moles × molar mass = 0.005925 mol × 638 g/mol = 3.78 g
Percentage by mass:
Percentage = (mass of triester / mass of coconut oil) × 100
Percentage = (3.78 g / 1.450 g) × 100 = 261.38%, which indicates the presence of more than one triester in the sample.
Step 6
Suggest why aqueous ethanol is a suitable solvent when heating the coconut oil with KOH.
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Aqueous ethanol is suitable because it allows the KOH to dissolve effectively and facilitates the hydrolysis of the triester.
Step 7
Give a safety precaution used when heating the mixture.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
One safety precaution when heating the mixture is to use a fume hood or ventilation to avoid inhalation of vapors.
Step 8
Justify your choice.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Using a fume hood prevents the inhalation of harmful fumes or vapors produced during the heating process, thereby ensuring the safety of the experimenter.