Photo AI

This question is about the reactions of alkanes - AQA - A-Level Chemistry - Question 1 - 2018 - Paper 2

Question icon

Question 1

This-question-is-about-the-reactions-of-alkanes-AQA-A-Level Chemistry-Question 1-2018-Paper 2.png

This question is about the reactions of alkanes. Alkanes can be used as fuels. Give an equation for the combustion of heptane (C₇H₁₆) in an excess of oxygen. Hept... show full transcript

Worked Solution & Example Answer:This question is about the reactions of alkanes - AQA - A-Level Chemistry - Question 1 - 2018 - Paper 2

Step 1

Give an equation for the combustion of heptane (C₇H₁₆) in an excess of oxygen.

96%

114 rated

Answer

The balanced equation for the combustion of heptane in oxygen is:

C7H16+11O27CO2+8H2OC₇H₁₆ + 11O₂ \rightarrow 7CO₂ + 8H₂O

Step 2

Identify a suitable catalyst for this process.

99%

104 rated

Answer

A suitable catalyst for the catalytic cracking of hexadecane is zeolite or aluminosilicate.

Step 3

Give one condition other than high temperature.

96%

101 rated

Answer

One condition for this process is using slight or moderate pressure.

Step 4

Give an equation for the catalytic cracking of one molecule of hexadecane to produce one molecule of heptane, one molecule of cyclohexane and one other product.

98%

120 rated

Answer

The equation for the catalytic cracking of hexadecane is:

C16H34C7H16+C6H12+C3H8C_{16}H_{34} \rightarrow C_7H_{16} + C_6H_{12} + C_3H_8

(where C6H12C_6H_{12} is cyclohexane and C3H8C_3H_8 is propane).

Step 5

Give equations for the propagation steps in the reaction of butane to form 2-chlorobutane.

97%

117 rated

Answer

The propagation steps for the chlorination of butane to form 2-chlorobutane are:

  1. Formation of a radical: C4H10+ClC3H7+HClC_4H_{10} + Cl^{\bullet} \rightarrow C_3H_{7}^{\bullet} + HCl

  2. Reaction of the radical with chlorine: C3H7+Cl2C3H7Cl+ClC_3H_{7}^{\bullet} + Cl_2 \rightarrow C_3H_7Cl + Cl^{\bullet}

Step 6

Identify the radical produced from this CFC that is responsible for the depletion of ozone in the atmosphere.

97%

121 rated

Answer

The radical produced from CFCs responsible for ozone depletion is the chlorine radical, Cl.

Step 7

Explain, with the aid of equations, why a single radical can cause the decomposition of many molecules of ozone.

96%

114 rated

Answer

A single chlorine radical can cause the decomposition of many ozone molecules by acting as a chain reaction catalyst. The mechanism involves:

  1. The reaction of the radical with ozone: Cl+O3ClO+O2Cl^{\bullet} + O_3 \rightarrow ClO^{\bullet} + O_2

  2. The reaction of the chlorine monoxide radical with another ozone molecule: ClO+O3Cl+2O2ClO^{\bullet} + O_3 \rightarrow Cl^{\bullet} + 2O_2

In this way, one chlorine radical can destroy numerous ozone molecules.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;