This question is about rates of reaction - AQA - A-Level Chemistry - Question 10 - 2021 - Paper 2
Question 10
This question is about rates of reaction.
Iodine and propanone react together in an acid-catalysed reaction
\[ CH_3C(=O)CH_3(aq) + I^-(aq) \rightarrow CH_3C(=O)I(aq... show full transcript
Worked Solution & Example Answer:This question is about rates of reaction - AQA - A-Level Chemistry - Question 10 - 2021 - Paper 2
Step 1
Suggest why the 1.0 cm³ portions of the reaction mixture are added to an excess of NaHCO₃ solution.
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Answer
The sodium hydrogencarbonate solution neutralises the acid catalyst. Therefore, it stops the reaction.
Step 2
Suggest why the order of this reaction with respect to propanone can be ignored in this experiment.
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Answer
The concentration/amount of propanone is much larger than 200 times larger than the concentration/amount of iodine. Consequently, the change in concentration in propanone is negligible.
Step 3
Draw a line of best fit.
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The graph should show a downward slope with appropriate points plotted. The line of best fit should pass through the majority of the points, minimizing the distance to the data points and avoiding any anomalous results.
Step 4
Explain how the graph shows that the reaction is zero-order with respect to iodine in the reaction between propanone and iodine.
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Answer
The graph is a straight line with a constant gradient. This indicates that the rate of reaction does not change as the concentration of iodine changes. Therefore, the reaction is zero-order with respect to iodine, as the reaction rate is independent of the concentration of iodine.
Step 5
Use Figure 8 to calculate a value for the activation energy (Eₐ), in kJ mol⁻¹, for this reaction.
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From the graph in Figure 8, the gradient is calculated as ( -E_a / R ). Using the provided values from the equation and substituting R = 8.31 J K⁻¹ mol⁻¹, the activation energy Eₐ is found to be approximately -123.30 to -221.30 kJ mol⁻¹, depending on the specific coordinates used.