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What is the mass, in mg, of carbon formed when 3.0 x 10^-3 mol of propene undergoes incomplete combustion? $$2C_3H_6 + 3O_2 ightarrow 6C + 6H_2O$$ - AQA - A-Level Chemistry - Question 11 - 2017 - Paper 3

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Question 11

What-is-the-mass,-in-mg,-of-carbon-formed-when-3.0-x-10^-3-mol-of-propene-undergoes-incomplete-combustion?--$$2C_3H_6-+-3O_2--ightarrow-6C-+-6H_2O$$-AQA-A-Level Chemistry-Question 11-2017-Paper 3.png

What is the mass, in mg, of carbon formed when 3.0 x 10^-3 mol of propene undergoes incomplete combustion? $$2C_3H_6 + 3O_2 ightarrow 6C + 6H_2O$$

Worked Solution & Example Answer:What is the mass, in mg, of carbon formed when 3.0 x 10^-3 mol of propene undergoes incomplete combustion? $$2C_3H_6 + 3O_2 ightarrow 6C + 6H_2O$$ - AQA - A-Level Chemistry - Question 11 - 2017 - Paper 3

Step 1

Calculate the moles of carbon formed

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Answer

From the balanced equation, for every 2 moles of propene (C3H6C_3H_6), 6 moles of carbon (C) are produced. Therefore, the moles of carbon produced can be calculated as:

ext{Moles of carbon} = 6 imes rac{3.0 imes 10^{-3} ext{ mol } C_3H_6}{2} = 9.0 imes 10^{-3} ext{ mol C}.

Step 2

Convert moles of carbon to mass

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Answer

To find the mass of carbon formed in grams, we use the molar mass of carbon, which is approximately 12 g/mol.

ext{Mass of carbon} = 9.0 imes 10^{-3} ext{ mol} imes 12 rac{ ext{g}}{ ext{mol}} = 0.108 ext{ g}.

To convert this to milligrams:

extMassinmg=0.108extgimes1000=108extmg. ext{Mass in mg} = 0.108 ext{ g} imes 1000 = 108 ext{ mg}.

Thus, the answer corresponds to option C: 1.08 x 10^2 mg.

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