The equation for the reaction between sulfur dioxide and oxygen is shown - AQA - A-Level Chemistry - Question 11 - 2019 - Paper 3
Question 11
The equation for the reaction between sulfur dioxide and oxygen is shown.
$$ ext{2SO}_2(g) + ext{O}_2(g) \rightleftharpoons \text{2SO}_3(g)$$
In an experiment, 2.... show full transcript
Worked Solution & Example Answer:The equation for the reaction between sulfur dioxide and oxygen is shown - AQA - A-Level Chemistry - Question 11 - 2019 - Paper 3
Step 1
Calculate the change in moles of the reaction
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Answer
Let the change in moles of SO2 that reacts be denoted as x. The balanced equation shows that for every 2 moles of SO2 reacted, 2 moles of SO3 are produced.
Starting with:
SO2: 2.00 mol
O2: 2.00 mol
SO3: 0 mol
At equilibrium, we have:
SO2: 2.00 - x mol
O2: 2.00 - (0.5)x mol (since 1 mole of O2 reacts with 2 moles of SO2)
SO3: 0 + x mol (it produces the same amount as consumed)
The total moles at equilibrium is:
extTotal=(2−x)+(2−0.5x)+x=3.40
Simplifying this:
extTotal=4−0.5x=3.40
Solving for x, we find:
ightarrow x = 1.20$$
Step 2
Determine the equilibrium moles of sulfur trioxide
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Answer
Using the value of x found, the moles of SO3 at equilibrium is:
extSO3=x=1.20extmol
Step 3
Calculate the total moles at equilibrium
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Answer
The total moles at equilibrium is 3.40 mol (given).
Step 4
Determine the mole fraction of sulfur trioxide
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Answer
The mole fraction (X) of a component is calculated as:
X=total molesmoles of component
