The equation for the reaction between zinc and hydrochloric acid is
Zn + 2HCl → ZnCl₂ + H₂
What is the minimum mass, in mg, of zinc (Ar = 65.4) needed to react with 50.0 cm³ of 1.68 mol dm⁻³ hydrochloric acid? - AQA - A-Level Chemistry - Question 19 - 2017 - Paper 3
Question 19
The equation for the reaction between zinc and hydrochloric acid is
Zn + 2HCl → ZnCl₂ + H₂
What is the minimum mass, in mg, of zinc (Ar = 65.4) needed to react wit... show full transcript
Worked Solution & Example Answer:The equation for the reaction between zinc and hydrochloric acid is
Zn + 2HCl → ZnCl₂ + H₂
What is the minimum mass, in mg, of zinc (Ar = 65.4) needed to react with 50.0 cm³ of 1.68 mol dm⁻³ hydrochloric acid? - AQA - A-Level Chemistry - Question 19 - 2017 - Paper 3
Step 1
Calculate the number of moles of hydrochloric acid
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Answer
First, we need to determine the number of moles of hydrochloric acid (HCl) in 50.0 cm³.
Using the formula:
n=cimesV
where:
n is the number of moles,
c is the concentration in mol dm⁻³,
V is the volume in dm³.
Convert volume from cm³ to dm³:
50.0extcm3=0.0500extdm3
Substituting the values:
n=1.68extmoldm−3imes0.0500extdm3=0.0840extmol
Step 2
Determine moles of zinc required
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Answer
From the balanced equation, we see that 1 mole of Zn reacts with 2 moles of HCl. Thus: