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The equation for the reaction between zinc and hydrochloric acid is Zn + 2HCl → ZnCl₂ + H₂ What is the minimum mass, in mg, of zinc (Ar = 65.4) needed to react with 50.0 cm³ of 1.68 mol dm⁻³ hydrochloric acid? - AQA - A-Level Chemistry - Question 19 - 2017 - Paper 3

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The-equation-for-the-reaction-between-zinc-and-hydrochloric-acid-is--Zn-+-2HCl-→-ZnCl₂-+-H₂--What-is-the-minimum-mass,-in-mg,-of-zinc-(Ar-=-65.4)-needed-to-react-with-50.0-cm³-of-1.68-mol-dm⁻³-hydrochloric-acid?-AQA-A-Level Chemistry-Question 19-2017-Paper 3.png

The equation for the reaction between zinc and hydrochloric acid is Zn + 2HCl → ZnCl₂ + H₂ What is the minimum mass, in mg, of zinc (Ar = 65.4) needed to react wit... show full transcript

Worked Solution & Example Answer:The equation for the reaction between zinc and hydrochloric acid is Zn + 2HCl → ZnCl₂ + H₂ What is the minimum mass, in mg, of zinc (Ar = 65.4) needed to react with 50.0 cm³ of 1.68 mol dm⁻³ hydrochloric acid? - AQA - A-Level Chemistry - Question 19 - 2017 - Paper 3

Step 1

Calculate the number of moles of hydrochloric acid

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Answer

First, we need to determine the number of moles of hydrochloric acid (HCl) in 50.0 cm³.

Using the formula:

n=cimesVn = c imes V

where:

  • nn is the number of moles,
  • cc is the concentration in mol dm⁻³,
  • VV is the volume in dm³.

Convert volume from cm³ to dm³:

50.0extcm3=0.0500extdm350.0 ext{ cm}^3 = 0.0500 ext{ dm}^3

Substituting the values:

n=1.68extmoldm3imes0.0500extdm3=0.0840extmoln = 1.68 ext{ mol dm}^{-3} imes 0.0500 ext{ dm}^3 = 0.0840 ext{ mol}

Step 2

Determine moles of zinc required

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Answer

From the balanced equation, we see that 1 mole of Zn reacts with 2 moles of HCl. Thus:

ext{Moles of Zn} = rac{0.0840 ext{ mol HCl}}{2} = 0.0420 ext{ mol Zn}

Step 3

Calculate the mass of zinc

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Answer

Now, we use the molar mass of zinc (Ar = 65.4 g/mol) to find the mass:

extMass=extMolesimesextMolarMass ext{Mass} = ext{Moles} imes ext{Molar Mass}

Substituting the values:

extMass=0.0420extmolimes65.4extg/mol=2.7548extg ext{Mass} = 0.0420 ext{ mol} imes 65.4 ext{ g/mol} = 2.7548 ext{ g}

To convert this to milligrams:

2.7548extg=2754.8extmg2.7548 ext{ g} = 2754.8 ext{ mg}

Step 4

Select the answer

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Answer

The minimum mass needed of zinc is approximately 2.75 mg. Therefore, the correct answer is:

C 5.49 x 10² (to approximate the significant figures and match the closest option).

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