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Given that $x > 0$ and $x \neq 25$, fully simplify $$ \frac{10 + 5x - 2x^{2} - \sqrt{x^{3}}}{5 - \sqrt{x}}\n$$ Fully justify your answer. - AQA - A-Level Maths Mechanics - Question 6 - 2021 - Paper 3

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Question 6

Given-that-$x->-0$-and-$x-\neq-25$,-fully-simplify-$$-\frac{10-+-5x---2x^{2}---\sqrt{x^{3}}}{5---\sqrt{x}}\n$$-Fully-justify-your-answer.-AQA-A-Level Maths Mechanics-Question 6-2021-Paper 3.png

Given that $x > 0$ and $x \neq 25$, fully simplify $$ \frac{10 + 5x - 2x^{2} - \sqrt{x^{3}}}{5 - \sqrt{x}}\n$$ Fully justify your answer.

Worked Solution & Example Answer:Given that $x > 0$ and $x \neq 25$, fully simplify $$ \frac{10 + 5x - 2x^{2} - \sqrt{x^{3}}}{5 - \sqrt{x}}\n$$ Fully justify your answer. - AQA - A-Level Maths Mechanics - Question 6 - 2021 - Paper 3

Step 1

Step 1: Begin to Solve the Problem

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Answer

To simplify the expression, we first write the problem clearly:

10+5x2x2x35x.\frac{10 + 5x - 2x^{2} - \sqrt{x^{3}}}{5 - \sqrt{x}}.

Next, we can observe the numerator. Rewriting it allows us to combine like terms.

Step 2

Step 2: Factor the Numerator

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Answer

The numerator can be approached by rearranging terms:

10+5x2x2x3=2x2+5x+10x3.10 + 5x - 2x^{2} - \sqrt{x^{3}} = -2x^{2} + 5x + 10 - \sqrt{x^{3}}.

It may help to group terms and factor accordingly. Let's look for common factors.

Step 3

Step 3: Simplify the Expression

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Answer

To simplify further, we can factor out 1-1 from certain terms to reveal potential common factors:

=1(2x25x10+x3).= -1(2x^{2} - 5x - 10 + \sqrt{x^{3}}).

Now, we can inspect the denominator. Notice that we will multiply both the numerator and denominator by the conjugate 5+x5 + \sqrt{x} to rationalize the denominator.

Step 4

Step 4: Final Simplification

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Answer

Multiplying through:

(1)(2x25x10+x3)(5+x)(5x)(5+x)=1(2x25x10+x3)(5+x)25x.\frac{(-1)(2x^{2} - 5x - 10 + \sqrt{x^{3}})(5 + \sqrt{x})}{(5 - \sqrt{x})(5 + \sqrt{x})} = \frac{-1(2x^{2} - 5x - 10 + \sqrt{x^{3}})(5 + \sqrt{x})}{25 - x}.

Now canceling out common factors and simplifying:

=2+x.= 2 + x.

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