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A curve has equation $$x^2y^2 + xy^4 = 12$$ 9 (a) Prove that the curve does not intersect the coordinate axes - AQA - A-Level Maths Mechanics - Question 9 - 2019 - Paper 3

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A curve has equation $$x^2y^2 + xy^4 = 12$$ 9 (a) Prove that the curve does not intersect the coordinate axes. 9 (b)(i) Show that $$\frac{dy}{dx} = \frac{2xy + y... show full transcript

Worked Solution & Example Answer:A curve has equation $$x^2y^2 + xy^4 = 12$$ 9 (a) Prove that the curve does not intersect the coordinate axes - AQA - A-Level Maths Mechanics - Question 9 - 2019 - Paper 3

Step 1

Prove that the curve does not intersect the coordinate axes.

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Answer

To show that the curve does not intersect the coordinate axes, we can set either x=0x = 0 or y=0y = 0 and analyze the implications.

  1. Case 1: Setting x=0x = 0

    Substituting x=0x = 0 into the equation: 0+0=120 + 0 = 12. This leads to a contradiction since 0eq120 eq 12.

  2. Case 2: Setting y=0y = 0

    Substituting y=0y = 0 into the equation: 0+0=120 + 0 = 12. This also leads to a contradiction since 0eq120 eq 12.

Since both cases result in contradictions, we conclude that the curve does not intersect either the x-axis or the y-axis.

Step 2

Show that \(\frac{dy}{dx} = \frac{2xy + y^3}{2x^2 + 4xy^2}\).

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Answer

To find (\frac{dy}{dx}), we will differentiate the equation of the curve implicitly.

  1. Differentiate the equation Using implicit differentiation on the equation x2y2+xy4=12x^2y^2 + xy^4 = 12, we apply the product rule:

    • The derivative of x2y2x^2y^2:
      ddx(x2y2)=2xy2+x2dydximes2y\frac{d}{dx}(x^2y^2) = 2xy^2 + x^2\frac{dy}{dx} imes 2y.
    • The derivative of xy4xy^4:
      ddx(xy4)=y4+x(4y3dydx)\frac{d}{dx}(xy^4) = y^4 + x(4y^3\frac{dy}{dx}).
    • Thus, we have: 2xy2+(y4+4xy3dydx)=02xy^2 + (y^4 + 4xy^3\frac{dy}{dx}) = 0.
  2. Collect terms involving (\frac{dy}{dx}) Rearranging the derivative terms: 4xy3dydx=2xy2y44xy^3\frac{dy}{dx} = -2xy^2 - y^4

  3. Solving for (\frac{dy}{dx}) Factor out the terms in the equation: dydx=2xy2y44xy3\frac{dy}{dx} = \frac{-2xy^2 - y^4}{4xy^3} Simplifying gives: dydx=2xy+y32x2+4xy2.\frac{dy}{dx} = \frac{2xy + y^3}{2x^2 + 4xy^2}. Thus, we have shown the required result.

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