A curve has equation
$$x^2y^2 + xy^4 = 12$$
9 (a) Prove that the curve does not intersect the coordinate axes - AQA - A-Level Maths Mechanics - Question 9 - 2019 - Paper 3
Question 9
A curve has equation
$$x^2y^2 + xy^4 = 12$$
9 (a) Prove that the curve does not intersect the coordinate axes.
9 (b)(i) Show that
$$\frac{dy}{dx} = \frac{2xy + y... show full transcript
Worked Solution & Example Answer:A curve has equation
$$x^2y^2 + xy^4 = 12$$
9 (a) Prove that the curve does not intersect the coordinate axes - AQA - A-Level Maths Mechanics - Question 9 - 2019 - Paper 3
Step 1
Prove that the curve does not intersect the coordinate axes.
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Answer
To show that the curve does not intersect the coordinate axes, we can set either x=0 or y=0 and analyze the implications.
Case 1: Setting x=0
Substituting x=0 into the equation:
0+0=12.
This leads to a contradiction since 0eq12.
Case 2: Setting y=0
Substituting y=0 into the equation:
0+0=12.
This also leads to a contradiction since 0eq12.
Since both cases result in contradictions, we conclude that the curve does not intersect either the x-axis or the y-axis.
Step 2
Show that \(\frac{dy}{dx} = \frac{2xy + y^3}{2x^2 + 4xy^2}\).
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Answer
To find (\frac{dy}{dx}), we will differentiate the equation of the curve implicitly.
Differentiate the equation
Using implicit differentiation on the equation x2y2+xy4=12, we apply the product rule:
The derivative of x2y2: dxd(x2y2)=2xy2+x2dxdyimes2y.
The derivative of xy4: dxd(xy4)=y4+x(4y3dxdy).
Thus, we have:
2xy2+(y4+4xy3dxdy)=0.
Collect terms involving (\frac{dy}{dx})
Rearranging the derivative terms:
4xy3dxdy=−2xy2−y4
Solving for (\frac{dy}{dx})
Factor out the terms in the equation:
dxdy=4xy3−2xy2−y4
Simplifying gives:
dxdy=2x2+4xy22xy+y3.
Thus, we have shown the required result.