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Suzanne is a member of a sports club - AQA - A-Level Maths Mechanics - Question 17 - 2018 - Paper 3

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Suzanne is a member of a sports club. For each sport she competes in, she wins half of the matches. 17 (a) After buying a new tennis racket Suzanne plays 10 matches... show full transcript

Worked Solution & Example Answer:Suzanne is a member of a sports club - AQA - A-Level Maths Mechanics - Question 17 - 2018 - Paper 3

Step 1

17 (a) Investigate whether Suzanne's new racket has made a difference

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Answer

To investigate this claim, we first state the hypotheses:

  • Null Hypothesis, H0H_0: The probability of winning a match with the new racket is the same as before, p=0.5p = 0.5.
  • Alternative Hypothesis, H1H_1: The probability of winning a match with the new racket is different, p0.5p \neq 0.5.

Next, we will use the Binomial distribution model, with the number of matches played ( n = 10 ) and the number of wins ( k = 7 ). Using the binomial probability formula:

P(X=k)=(nk)pk(1p)nkP(X = k) = \binom{n}{k} p^k (1-p)^{n-k}

The probabilities we are interested in are P(X6)P(X \leq 6) and P(X7)P(X \geq 7), which we calculate separately.

  1. Calculate P(X6)P(X \leq 6):

    • Using cumulative binomial tables or a calculator, we find: P(X6)=1P(X7)P(X \leq 6) = 1 - P(X \geq 7)
    • This gives us P(X6)0.8281P(X \leq 6) \approx 0.8281 or 0.1720.172.
  2. Compare this result with the significance level of 0.10:

    • Since P(X7)P(X \geq 7) is roughly 0.1720.172, and 0.172>0.100.172 > 0.10, we do not reject the null hypothesis.

Conclusion: There is insufficient evidence that Suzanne's new racket has made a difference.

Step 2

17 (b) Find the minimum number of matches Suzanne must win

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Answer

For the second part, we again denote the number of matches played as ( n = 20 ). We need to estimate the boundary for winning a proportion of matches to conclude there is a significant improvement at the 10% level of significance:

  • Let's denote ( k ) as the number of wins needed for significance.
  • The requirements state that we want: P(Xk)>0.1P(X \geq k) > 0.1

We express this in terms of the cumulative binomial probability:

  • Calculate P(Xk1)P(X \leq k-1), ensuring this value is less than 0.9:
    • Begin testing values for ( k ):
    • For k=14k = 14:
    • Cumulative Probability ( P(X \leq 13) ) is about 0.57710.5771, which shows that P(X14)=10.5771=0.4229>0.1P(X \geq 14) = 1 - 0.5771 = 0.4229 > 0.1. Hence, it is too low.
    • When evaluating ( k = 15 ), ( P(X \leq 14) ) results in approximately 0.69080.6908. Thus, (16)P(X15)0.8254(16) \Rightarrow P(X \leq 15) \approx 0.8254. This is also too low.
    • Finally, checking ( k = 17 ), we find this meets the condition.

Thus, the minimum number of matches Suzanne must win is 14 for her to conclude that the new racket has improved her performance.

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